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Vedmedyk [2.9K]
4 years ago
14

Find the area of the circle. Round your answer to the nearest tenth.

Mathematics
2 answers:
Lyrx [107]4 years ago
6 0

Answer:

254.47 to the nearest tenth is 254.5mm

Step-by-step explanation:

Hey! here's explanation:

A= π x r^2 (squared)

so A = π x 9mm^2

which gives you the answer of 254.47

TO THE NEAREST TENTH IS 254.5!

*hope this helps!*

jek_recluse [69]4 years ago
4 0
The Answer Is: 254.47
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The ratio of grade 7's to grade 8's is 5:3. If there
Greeley [361]

Answer:

240 students

Step-by-step explanation:

Grade 7 : Grade 8 = 5 : 3

Number of seventh grade students = 5x

Number of Eighth grade students = 3x

3x = 90

x = 90÷3

x = 30

Total students = 5x + 3x = 8x = 8 * 30 = 240

5 0
3 years ago
√(5-2x) - √(2-x) = 1
Eva8 [605]
Square both sides. (5-2x) - (2-x) = 1^2. 5 - 2x - 2 + x = 1. Simplify to get 3 - x = 1. X=2
8 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
Which is equal to cos47°?
Murrr4er [49]

Which of these is equal to cos 47°?

a. cos 43°

b. sin 43°

c. tan 43°

d. cos 133°

B.....

cos (47°)= sin (90°-47°)=sin (43°) [complementary angles]

Answer B

7 0
3 years ago
Write the word sentence as an inequality.<br><br> Three times a number h is at least -12 .
natima [27]

Answer:

Step-by-step explanation:

3h<-12

3 0
3 years ago
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