Question

Hi how can I graph this if it dosn't have a slope? 1. y = (2/3)x - 1 y = -x + 4

Answer 1

System of Linear Equations entered :

[1] y - 2x/3 = -1

[2] y + x = 4

// To remove fractions, multiply equations by their respective LCD

Multiply equation [1] by 3

// Equations now take the shape:

[1] 3y - 2x = -3

[2] y + x = 4

Graphic Representation of the Equations :

-2x + 3y = -3 x + y = 4

Solve by Substitution :

// Solve equation [2] for the variable x

[2] x = -y + 4

// Plug this in for variable x in equation [1]

[1] 3y - 2•(-y +4) = -3

[1] 5y = 5

// Solve equation [1] for the variable y

[1] 5y = 5

[1] y = 1

// By now we know this much :

y = 1

x = -y+4

// Use the y value to solve for x

x = -(1)+4 = 3

I hope this help you