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ratelena [41]
3 years ago
13

The graph of the line through (2, 3) that is perpendicular to the line with

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

  H  (2, -4)

Step-by-step explanation:

The given line is a horizontal line, so a perpendicular will be a vertical line. Its equation will be of the form ...

  x = constant

In order for that line to go through (2, 3), the constant must be the x-coordinate, 2. So, the perpendicular line to y=-1 is ...

  x = 2.

It will go through any point with an x-coordinate of 2, but will not go through any point with any other x-coordinate. So, the appropriate answer choice is the point ...

  (2, -4)

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On Saturday Lindsay walked 3 1/2 mile in 1 and 2/5 hours what was her walking pace in miles per hour write in simplest form
Makovka662 [10]

Answer:

If she walked 3.5 miles in 1.4 hours, then her pace was:

 3.5 miles / 1.4 hours = 2.5 miles/hour

Step-by-step explanation:

To get her pace in miles per hour, you take the number of miles and divide by the number of hours.  

7 0
3 years ago
Find the slope between:<br> (1,-2)<br> (2,-2)
stiks02 [169]

Answer: the slope would be 0

Step-by-step explanation:

7 0
2 years ago
What is the surface area of the right prism below?
-Dominant- [34]

Answer:

120 sq. units

plus them all and add 100

3 0
3 years ago
Read 2 more answers
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
What is the domain of F(x) = In(x)?
jekas [21]

Answer as an inequality:  x > 0

Answer in interval notation:  (0, \infty)

Answer in words: Set of positive real numbers

All three represent the same idea, but in different forms.

======================================================

Explanation:

Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is f^{-1}(x) = \log_b(x)

For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.

Because of this, \log_b(x) has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.

The domain of \log_b(x) is x > 0 which in interval notation would be (0, \infty). This is the interval from 0 to infinity, excluding both endpoints.

------------------------

The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.

So,

\log_e(x) = \text{Ln}(x)

allowing all of what was discussed in the previous section to apply to this Ln(x) function as well.

------------------------

In short, the domain is the set of positive real numbers. We can't have x be 0 or negative.

8 0
3 years ago
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