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REY [17]
3 years ago
6

Given h(x)=5x+1, find h(2)

Mathematics
2 answers:
Ket [755]3 years ago
6 0

Answer: h(2) = 11

Step-by-step explanation:

Plug in 2 for x

5(2)+1

10+1

11

Wittaler [7]3 years ago
5 0

Answer:

11

Step-by-step explanation:

h(x) =5x+1

h(x=2) is h(2)

h(2)= 5*2+1

=10+1

=11

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Answer:

An eggcellent yolk. It always cracks me up.

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Solve for z.<br><br> z12≤3<br><br> z≥36<br><br> z≤36<br><br> z≥4<br><br> z≤4
erastova [34]

Answer:

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5 0
3 years ago
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A silo is not the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cu
Gnom [1K]

Answer:

$7803.72

Step-by-step explanation:

We have been given that a silo is in the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cubic meter. We are asked to find the total cost to fill the silo with soybeans.

First of all, we will find the volume of silo using volume of cone formula.

\text{Volume of cone}=\frac{1}{3}\pi r^2 h, where,

r = radius

h = Height

We know that radius is half the diameter, so radius of silo would be r=\frac{3}{2}=1.5.

\text{Volume of cone}=\frac{1}{3}\pi (1.5\text{ m})^2 (8)\text{ m}

\text{Volume of cone}=\frac{1}{3}\pi\times 2.25\text{ m}^2 (8)\text{ m}

\text{Volume of cone}=\pi\times 0.75\text{ m}^2 (8)\text{ m}

\text{Volume of cone}=\pi\times 6\text{ m}^3

\text{Volume of cone}=18.8495559\text{ m}^3

Now we will multiply total volume by $414 to find total cost.\

\text{Total cost of soybeans}=\$414 \times 18.8495559

\text{Total cost of soybeans}=\$7803.7161426

\text{Total cost of soybeans}\approx \$7803.72

Therefore, it will cost $7803.72 to fill the silo with soybeans.

5 0
2 years ago
How many units is 1 from -6 on a number line
iVinArrow [24]
Find this by subtracting the two terms and then finding the absolute value of the difference.

1-(-6)= 7
|7|= 7

Final answer: 7
8 0
3 years ago
Two thirds times three eighths
LekaFEV [45]

Answer:

1/4 or 0.25

Step-by-step explanation:

2/3*3/8=6/24=1/4

3 0
2 years ago
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