Lol seems like elementary but 17.50 minus 9.50 equals 8 so the basic change is 8. X'D I cant believe this is college X'D
Answer:
The results don't make sense
Step-by-step explanation:
We can solve by means of a 2x2 system of equations, we have to:
"x" is the number of children's tickets
"y" is the number of adult tickets
Thus:
8 * x + 8.75 * y = 259
x + y = 35 => x = 35 - y
replacing we have:
8 * (35 - y) + 8.75 * y = 259
280 - 8 * y + 8.75 * y = 259
- 8 * y + 8.75 * y = 259 - 280
0.75 * y = -21
y = -21 / 0.75
y = -28
Thus:
x = 35 - (-28) = 63
With these results we notice that the problem has inconsistency, since the value of the tickets cannot be given a negative number, I recommend reviewing the problem, since the approach is correct.
We may have this planned like this:
two years is 8 quarters
<span>Assuming simple interest, </span>
You will use the formula
<span>A = P(1+rt) </span>
<span>= 400(1+8*.03) </span>
<span>= 496
</span>I think this is the answer:) Hope it helps a lot
Answer:
(1)Base Area= 81 square yards.
(2)
-
6 ft long and 8 ft wide
- 24 ft long and 2 ft wide
(3)Height=12 Units
Step-by-step explanation:
<u>Question 1</u>
Volume of the rectangular prism=2,592 cubic yards.
Height of the rectangular prism=32 yards
Volume of a rectangular prism =lbh (where lb is the Base Area)
Therefore:
lbh=2592
32lb=2592
lb=2592/32=81
Base Area= 81 square yards.
<u>Question 2</u>
Volume of the rectangular prism=432 cubic feet.
Height of the rectangular prism=9 feet
Volume of a rectangular prism =lbh (where lb is the Base Area)
Therefore:
lbh=432
9lb=432
lb=432/9=48
Base Area= 48 square yards.
Any dimension whose product is 48 is a possible choice.
They are:
- 3 ft long and 16 ft wide
-
6 ft long and 8 ft wide
- 24 ft long and 2 ft wide
<u>Question 3</u>
<u />
Volume of the rectangular prism=960 cubic units.
Base Area of the rectangular prism, lb=80 Square Units
Volume of a rectangular prism =lbh (where lb is the Base Area)
Therefore:
lbh=960
80h=960
h=960/80=12
Height= 12 units.
sana ang wala paako sagot ehh sana my sumagot
