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Bond [772]
3 years ago
15

An arithmetic sequence is shown below. You are not given many terms of this sequence, but you do have enough to fill in the miss

ing number. What number goes in the blank?
12, _, 54, ...
Mathematics
2 answers:
Mnenie [13.5K]3 years ago
7 0
Hello there.
<span>
An arithmetic sequence is shown below. You are not given many terms of this sequence, but you do have enough to fill in the missing number. What number goes in the blank?

12, _, 54, ...

</span>33
nirvana33 [79]3 years ago
4 0
For this, we use the equation for arithmetic sequence. It is given as:

an = a1 + (n-1)d

where an is the value at n term, a1 is the first term and d is the common difference

For 54,
54 = 12 + (3 -1)d
d = 21

an = 12 + (2-1)21
an = 33
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jade ran six miles around her neighbor hood to complete one mile. how many times will she need to run to complete 5/6 of a mile
Vera_Pavlovna [14]
5 times around <span>her neighbor hood to complete one mile

Please make me the brainiest answer.


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5 0
3 years ago
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Select the correct answer from the drop-down menu. consider the equations y = |x − 1| and y = 3x 2. the approximate solution of
kaheart [24]

The approximate solution of this system of equations is

(x,y)=(-0.25,1.25)

<h3>What is an equation?</h3>

Equation is defined as the state of being equal and is often shown as a math expression with equal values on either side, or refers to a problem where many things need to be taken into account.

Given that,

y = |x − 1| and y = 3x+2

 y = |x − 1|

    = (x-1) ,    for  (x-1)>0 or x>1

and

y = -(x-1)  ,    for(x-1)<0  or x<1

y  = -x+1      

Now,   For x>1

y = x-1    ......(1)

y = 3x+2   ......(2)

Solving for x by equaliting's method:

 3x+2 = x-1

→ 3x-x = -1-2

→ 2x = -3

→ x = -3/2

→ x = -1.5 which is <1.

For x<1

y = -x+1    ......(1)

y = 3x+2   ......(2)

Solving for x by equaliting's method:

 3x+2 = -x+1

→ 3x+x = 1-2

→ 4x = -1

→ x = -1/4

→ x= -0.25 which is <1.

substitute the value of x = -0.25 in equation 1 for x<1.

y = -x+1

  = -(-0.25)+1

y  = 1.25

Hence, The approximate solution of this system of equations is

(x,y)=(-1/4,5/4)=(-0.25,1.25).

To learn more about equation from the given link:

brainly.com/question/9475812

#SPJ4

   

8 0
2 years ago
The diameter of a regulatiom soccer ball is about 8 3/5 inches
alina1380 [7]

8 3/5 is between 8 and 9

 so point D would be correct

5 0
3 years ago
Given that y varies directly with x in the table below, what is the value of y if the value of x is 7?
ra1l [238]
Function of equation is x * 6 = y

Using this, 7 x 6 = 42.

Your answer is c, or 42.
7 0
3 years ago
Read 2 more answers
Suppose an arrow is shot upward on the moon with a velocity of 44 m/s, then its height in meters after tt seconds is given by h(
andreev551 [17]

Answer:

a. 38.19m/s

b. 38.605m/s

c. 38.937m/s

d. 39.0117m/s

e. 39.01917m/s

Step-by-step explanation:

The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}

Where:

x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval

a. Let's find h(3) and h(4) using the data provided by the problem:

h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f

The average velocity over the interval [3, 4] is :

v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s

b. Let's find h(3.5) using the data provided by the problem:

h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f

The average velocity over the interval [3, 3.5] is :

v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s

c. Let's find h(3.1) using the data provided by the problem:

h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f

The average velocity over the interval [3, 3.1] is :

v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s

d. Let's find h(3.01) using the data provided by the problem:

h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f

The average velocity over the interval [3, 3.01] is :

v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s

e. Let's find h(3.001) using the data provided by the problem:

h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f

v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s

7 0
3 years ago
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