5 times around <span>her neighbor hood to complete one mile
Please make me the brainiest answer.
</span>
The approximate solution of this system of equations is
(x,y)=(-0.25,1.25)
<h3>What is an equation?</h3>
Equation is defined as the state of being equal and is often shown as a math expression with equal values on either side, or refers to a problem where many things need to be taken into account.
Given that,
y = |x − 1| and y = 3x+2
y = |x − 1|
= (x-1) , for (x-1)>0 or x>1
and
y = -(x-1) , for(x-1)<0 or x<1
y = -x+1
Now, For x>1
y = x-1 ......(1)
y = 3x+2 ......(2)
Solving for x by equaliting's method:
3x+2 = x-1
→ 3x-x = -1-2
→ 2x = -3
→ x = -3/2
→ x = -1.5 which is <1.
For x<1
y = -x+1 ......(1)
y = 3x+2 ......(2)
Solving for x by equaliting's method:
3x+2 = -x+1
→ 3x+x = 1-2
→ 4x = -1
→ x = -1/4
→ x= -0.25 which is <1.
substitute the value of x = -0.25 in equation 1 for x<1.
y = -x+1
= -(-0.25)+1
y = 1.25
Hence, The approximate solution of this system of equations is
(x,y)=(-1/4,5/4)=(-0.25,1.25).
To learn more about equation from the given link:
brainly.com/question/9475812
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8 3/5 is between 8 and 9
so point D would be correct
Function of equation is x * 6 = y
Using this, 7 x 6 = 42.
Your answer is c, or 42.
Answer:
a. 38.19m/s
b. 38.605m/s
c. 38.937m/s
d. 39.0117m/s
e. 39.01917m/s
Step-by-step explanation:
The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

Where:

a. Let's find h(3) and h(4) using the data provided by the problem:

The average velocity over the interval [3, 4] is :

b. Let's find h(3.5) using the data provided by the problem:

The average velocity over the interval [3, 3.5] is :

c. Let's find h(3.1) using the data provided by the problem:

The average velocity over the interval [3, 3.1] is :

d. Let's find h(3.01) using the data provided by the problem:

The average velocity over the interval [3, 3.01] is :

e. Let's find h(3.001) using the data provided by the problem:

