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NemiM [27]
3 years ago
5

Which tissue would likely have cells with the greatest number of gap junctions? Which tissue would likely have cells with the gr

eatest number of gap junctions? Bone Cardiac muscle The mucosal layer of the GI tract Epidermis
Biology
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer: cardiac muscle

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Toxoplasma is a protist that must infect cats to be able to reproduce. The infection doesn’t benefit cats and only rarely harms
marin [14]

Answer:

The correct answer is : parasitism.

Explanation:

Parasitism is a symbiosis relationship in which two organism lives together but only one is benefited and other harm in any means. Toxoplasma is, in this case, parasite which is benefited while cats are host and harmed in this relationship.

Degree and chances of harm or benefit do not defines the symbiosis relationship between two organism. Cats are rarely harmed but still harmed in this relationship.

Thus, the correct answer is : parasitism.

4 0
3 years ago
Which term is defined as the exact location where an earthquake occured
kkurt [141]

Answer:

Hypocenter is the exact location beneath the earths surface where the earthquake began.

hope it helps:)

7 0
3 years ago
Read 2 more answers
After stranuous exercise sore muscles can often occur because of?
Bezzdna [24]
C. A buildup of lactic acid in the tissues. 
7 0
3 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
3 years ago
Earth’s biosphere is
irakobra [83]
One of the 4 layers that surrounds the earth.
8 0
3 years ago
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