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Maru [420]
4 years ago
12

Which inequality has the same value for x as the inequality - 2x > -14

Mathematics
1 answer:
Arisa [49]4 years ago
7 0

Answer:

D

Step-by-step explanation:

Solve all inequalities.

Given inequality:

-2x>-14\ [\text{Divide by -2, this will change the sign of the inequality}]\\ \\x

A.

-7x7

B.

3.5>-0.5x\ [\text{Divide by -0.5, this will change the sign of the inequality}]\\ \\-7-7

C.

3x\le 21\ [\text{Divide by 3}]\\ \\x\le 7

D.

35>5x\ [\text{Divide by 5}]\\ \\7>x\\ \\x

As you can see inequality in option D has the same solution set as given inequality.

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Answer:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be 1-0.99 =0.01 and the value of \alpha/2 =0.005. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

z_{\alpha/2}= \pm 2.576

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

\alpha=0.01, n =26, \sigma = 28.9

We want to construct a confidence interval at 99% of confidence, so then the significance level would be 1-0.99 =0.01 and the value of \alpha/2 =0.005. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

z_{\alpha/2}= \pm 2.576

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0
3 years ago
Are the equation linear or nonlinear?​
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Answer:

<em>Results below</em>

Step-by-step explanation:

<u>Equation of the line</u>

A straight line can be written in the form:

y = ax + b

Where a and b are constants and x is the independent variable.

The essential condition for an equation to be linear is that the x must be powered to the exponent 1, which is usually not written.

From the equations presented in the table:

y = x^1+2 is linear because the exponent of the x is 1

y = 5(x+2) = 5x + 10 is linear with a=5 and b=10.

y = x is linear with a=1 and b=0

y = x^2+1 is not linear because the exponent of x is 2

y = x(x) = x^2 is not linear because the exponent of x is 2

The table below summarizes the results

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