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Ahat [919]
3 years ago
8

Will give brainliest

Mathematics
2 answers:
nadya68 [22]3 years ago
5 0

Answer:

The answer to your question is A

Step-by-step explanation:


Snezhnost [94]3 years ago
3 0
I believe it's the first option. Hope this helps.
You might be interested in
Sarah kept track of the points she scored during her first five basketball games in the table shown. easy help
AURORKA [14]

Answer:

E

Step-by-step explanation:

If you add 22 onto the sum of all the points and divide by the amount of games (6), you get 12.

8 0
3 years ago
Find the length of the hypothenuse of the right triangle with legs that measure 5 and 7. Brianlest for anyone who can give step
zepelin [54]
To calculate hypothenuse you use the formula a^2+b^2=c^2 where c is the length of the hypothenuse.

1. 5^2+7^2=c^2
2.25+49=74
3. Now you will square root the 74
4. The hypothenuse is equal to 8.6
4 0
3 years ago
Pleasssseeee hellllpllllllppppp???????
olchik [2.2K]

Answer:

f(x) and g(x) are inverse functions

Step-by-step explanation:

In the two functions f(x) and g(x) if, f(g(x)) = g(f(x)) = x, then

f(x) and g(x) are inverse functions

Let us use this rule to solve the question

∵ f(x) = 3x²

∵ g(x) = \sqrt{\frac{x}{3}}

→ Find f(g(x)) by substitute x in f(x) by g(x)

∴ f(g(x)) = 3(\sqrt{\frac{x}{3}})²

→ Cancel the square root with power 2

∴ f(g(x)) = 3(\frac{x}{3})

→ Cancel the 3 up with the 3 down

∴ f(g(x)) = x

→ Find g(f(x)) by substitute x in g(x) by f(x)

∴ g(f(x)) = \sqrt{\frac{3x^{2}}{3}}

→ Cancel the 3 up with the 3 down

∴ g(f(x)) = \sqrt{x^{2}}

→ Cancel the square root with power 2

∴ g(f(x)) = x

∵ f(g(x)) = g(f(x)) = x

→ By using the rule above

∴ f(x) and g(x) are inverse functions

5 0
2 years ago
.yhuogyhuogyuofgftyuofyufyhuo
Alina [70]

Answer:

What did you do? What is this mess but thanks for the points

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
HELP!! What is the approximate measure of angle x in the triangle shown?
Alex Ar [27]
<h3>Answer:   D)  130.5 degrees</h3>

=================================================

Work Shown:

c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\

Note: I used the law of cosines. Make sure your calculator is in degree mode.

6 0
3 years ago
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