x+y+z=1
x=1/(y+z)
1/(y+z)-2y+3z=2
1-2y²-2yz+3yz+3z²=2(y+z)
(1-2y²+yz+3z²)/2=y+z
z=(1-2y²+yz+3z²)/2 -y/1
z=(1-2y²+yz+3z²-2y)/2
Answer:
lines a and b
Step-by-step explanation:
A negative slope makes the line face leftward so that leaves a and b.
A. 6/77
B. 7/17
C. 1/24
D. 6/19
E. 7
55
Answer: x(-2,0) y(0,1.4)