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sveta [45]
3 years ago
12

If b= the number of blue bikes, which algebraic expression represents the

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
It should be c! because the sum of blue bikes is b plus the 9 more!!
valkas [14]3 years ago
6 0

Answer:

C

Step-by-step explanation:

If B = blue bikes

sum = addition

and 9 = red bikes

so B+9

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After creating a hypothesis, Janis decides how to best measure the impact of her manipulation. This variable that is impacted by
Alexandra [31]

Answer:

This variable that is impacted by manipulating the independent variable is known as dependent variable

Step-by-step explanation:

One of the methods to test a hypothesis is the use of independent variable. The independent variable is manipulated to know if the change will be effective or not.

The variable which will be impacted by the independent variable is called dependent variable. The researcher manipulated the values for independent variable to check if the dependent variable changes or not ..

7 0
3 years ago
Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m
Elenna [48]

Answer:

Part a: <em>The probability of no arrivals in a one-minute period is 0.000045.</em>

Part b: <em>The probability of three or fewer passengers arrive in a one-minute period is 0.0103.</em>

Part c: <em>The probability of no arrivals in a 15-second is 0.0821.</em>

Part d: <em>The probability of at least one arrival in a 15-second period​ is 0.9179.</em>

Step-by-step explanation:

Airline passengers are arriving at an airport independently. The mean arrival rate is 10 passengers per minute. Consider the random variable X to represent the number of passengers arriving per minute. The random variable X follows a Poisson distribution. That is,

X \sim {\rm{Poisson}}\left( {\lambda = 10} \right)

The probability mass function of X can be written as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

Substitute the value of λ=10 in the formula as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{{\left( {10} \right)}^x}}}{{x!}}

​Part a:

The probability that there are no arrivals in one minute is calculated by substituting x = 0 in the formula as,

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}}\\\\ = {e^{ - 10}}\\\\ = 0.000045\\\end{array}

<em>The probability of no arrivals in a one-minute period is 0.000045.</em>

Part b:

The probability mass function of X can be written as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

The probability of the arrival of three or fewer passengers in one minute is calculated by substituting \lambda = 10λ=10 and x = 0,1,2,3x=0,1,2,3 in the formula as,

\begin{array}{c}\\P\left( {X \le 3} \right) = \sum\limits_{x = 0}^3 {\frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}}} \\\\ = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^1}}}{{1!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^2}}}{{2!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^3}}}{{3!}}\\\\ = 0.000045 + 0.00045 + 0.00227 + 0.00756\\\\ = 0.0103\\\end{array}

<em>The probability of three or fewer passengers arrive in a one-minute period is 0.0103.</em>

Part c:

Consider the random variable Y to denote the passengers arriving in 15 seconds. This means that the random variable Y can be defined as \frac{X}{4}

\begin{array}{c}\\E\left( Y \right) = E\left( {\frac{X}{4}} \right)\\\\ = \frac{1}{4} \times 10\\\\ = 2.5\\\end{array}

That is,

Y\sim {\rm{Poisson}}\left( {\lambda = 2.5} \right)

So, the probability mass function of Y is,

P\left( {Y = y} \right) = \frac{{{e^{ - \lambda }}{\lambda ^y}}}{{y!}};x = 0,1,2, \ldots

The probability that there are no arrivals in the 15-second period can be calculated by substituting the value of (λ=2.5) and y as 0 as:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = {e^{ - 2.5}}\\\\ = 0.0821\\\end{array}

<em>The probability of no arrivals in a 15-second is 0.0821.</em>

Part d:  

The probability that there is at least one arrival in a 15-second period is calculated as,

\begin{array}{c}\\P\left( {X \ge 1} \right) = 1 - P\left( {X < 1} \right)\\\\ = 1 - P\left( {X = 0} \right)\\\\ = 1 - \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = 1 - {e^{ - 2.5}}\\\end{array}

            \begin{array}{c}\\ = 1 - 0.082\\\\ = 0.9179\\\end{array}

<em>The probability of at least one arrival in a 15-second period​ is 0.9179.</em>

​

​

7 0
3 years ago
I have free points to give. If you want points, I will give them away for free. I give points daily. My only request is to give
Pie

Answer:

ok!

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Anyone know how to do this? If so plz help
bekas [8.4K]

NOTES:

Use the equation y = mx + b where m is the unit rate and b is the one-time flat fee

1. Answer:

\begin {array}{c||c|c|c|c}x&0&1&2&3\\ y&70.00&70.20&70.40&70.60\\\end{array}

<u>Step-by-step explanation:</u>

coffee maker costs $70 - this is a one-time flat fee

it costs $0.20 per cup of coffee - this is the unit rate

y = 0.20x + 70

y = 0.20(0) + 70   →   y = 0.00 + 70   →   y = 70.00

y = 0.20(1) + 70   →   y = 0.20 + 70    →   y = 70.20

y = 0.20(2) + 70   →   y = 0.40 + 70   →   y = 70.40

y = 0.20(3) + 70   →   y = 0.60 + 70   →   y = 70.40

*******************************************************************************

2. Answer:

\begin {array}{c||c|c|c|c}x&1&2&3&4\\ y&4.50&6.00&7.50&9.00\\\end{array}

<u>Step-by-step explanation:</u>

shoes costs $3.00 - this is a one-time flat fee

it costs $1.50 per game of bowling - this is the unit rate

y = 1.50x + 3.00

y = 1.50(1) + 3.00  →    y = 1.50 + 3.00   →   y = 4.50

y = 1.50(2) + 3.00  →   y = 3.00 + 3.00   →   y = 6.00

y = 1.50(3) + 3.00  →   y = 4.50 + 3.00   →   y = 7.50

y = 1.50(4) + 3.00  →   y = 6.00 + 3.00   →   y = 9.00

*******************************************************************************

3. Answer: Negative

<u>Step-by-step explanation:</u>

As the x-values increase, the y-values decrease.  Opposite directions results in a negative slope.

*******************************************************************************

4. Answer: Gym A → y = 20x + 50    Gym B → y = 25x + 30

<u>Step-by-step explanation:</u>

Use the slope formula: m = \dfrac{y_2-y_1}{x_2-x_1}.  Then choose ONE of the points and input the point (x₁, y₁) and slope (m) into the Point-Slope formula: y - y₁ = m(x - x₁) and solve for y.

Gym A: (x₁, y₁) = (1, 70) and (x₂, y₂) = (2, 90)

m=\dfrac{90-70}{2-1} = \dfrac{20}{1} = 20

y - 70 = 20(x - 1)

y - 70 = 20x - 20

y        = 20x + 50

Gym B: (x₁, y₁) = (1, 55) and (x₂, y₂) = (2, 80)

m=\dfrac{80-55}{2-1} = \dfrac{25}{1} = 25

y - 55 = 25(x - 1)

y - 55 = 25x - 25

y        = 25x + 30


5 0
3 years ago
Please help me it is due in 10 minutes
MAXImum [283]

Answer:

whooops no one had answered u from 50 min!

3 0
2 years ago
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