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slava [35]
3 years ago
15

jenny is painting a toy chest that she made for her little brother. if the box is 4 feet long, 3 feet wide, and 2 feel tall, wha

t is the surface area of the box to be painted? Okay so i think i have it figured out, would the surface area be 42??
Mathematics
1 answer:
horsena [70]3 years ago
7 0
You would have to multiply all the numbers. 4 X 3, 4 X 2, 3 X 2, the answer I got was 36.
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Katie has read 32% of a book. If she has read 80 pages, how many more pages does Katie have left to read? Please explain
yawa3891 [41]
Keep note of these things before we start:
-Of is a keyword that tells us multiplication is being done
-x = total number of pages
-32% = 32/100 = .32

Okay, here we go:
32% of total number of pages = 80
.32 of x = 80
.32*x = 80
.32x = 80
.32x/.32 = 80/.32
x = 250

There are 250 pages in total in Katie's book.
To find out how many pages she has to read (y), subtract the pages read from the total:
TOTAL - PAGES READ = PAGES LEFT TO READ
250 - 80 = y
170 = y

Katie has 170 pages left to read
Hope this helps!
8 0
3 years ago
Determine a possible 3rd degree polynomial function in factored form with its only zeros at (4,0) and (-1,0) and (-7,0)
babunello [35]
4,9 equals 17 triven - 3 sued secton, 2 blue suction
And I Purple section
To Find - probability
Solutions:
P
=
Favarable out comes
Total Outcomes
• P/ Land on ried).
3
-N
3+2+1
And p (Lands on blue) = SAT
I
3
And p/Lands on Purple)=
Hence, Answer aol
P(red).
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3 0
2 years ago
I need help with these questions!!<br> 25 points!!!!<br> That’s what I have
Troyanec [42]

Answer:

7. D

8. A

9. D

10. B

11 A)  640 = 0.8j

11 B)   \frac{0.8j}{1.15}

Step-by-step explanation:

7.

Let Emmet work for "m" minutes

Since, Cal worked 4times as this, we can say Cal worked for "4m" minutes

Now, the total time (CAL + EMMET) is 720, so we SUM UP their individual times' expression and equate to 720. Shown below:

4m + m = 720

This is Answer choice D

8.

Let s be the price of each shirt

Each shirt costs "s" each, so 4 shirts cost "4s" in total.

4 shirts costs 60 AFTER 10 dollar discount, so before discount, it was:

60 + 10 = 70 dollars

Hence, 4 shirts cost 70 dollars BEFORE discount, so we can say:

4s = 70

But none of the choices are this, we need to simply manipulate this equation to get our answer (from choices).

<em>How did we get 70? We added 60 and 10. So we can put "60" on the right hand side and "-10" on the left hand side to get:</em>

<em>4s - 10 = 60</em>

<em />

<em>This is ultimatley 4s = 70</em>

<em>So the correct answer choice is A</em>

9.

Let Tony's age be "y"

We know grandmother is "3 years MORE than 6 times TONY (y)", thus we can write:

Grandmother is "6y + 3"

Total sum of them both is 87. Thus we can SUM both these expressions and equate to 87. Thus,

y + 6y + 3 = 87

D is the correct choice.

10.

THe total length is "f"

Each piece cut is 3/4

So the number of pieces is the total by each piece, so that is

\frac{f}{\frac{3}{4}}

All these "number of pieces" makes 6 shelves (since he used all), so we equate this expression to "6".   Now we have:

\frac{f}{\frac{3}{4}}=6

That is answer choice B

11 A)

Let Jocelyn's computer's price be "j",

Adrian's is 640, which is 20% LESS THAN Jocelyn's (j), so we can say:

640 is 20% less than "j"

or

"20% less than j" would be:

j - 0.2j = 0.8j

Now, we can write:

640 = 0.8j

11 B)

We can say:

Adrian is 15% more than Corbin

or

A = 0.15C + C

A = 1.15C

[note: let adrian's computer price be A and Corbin's computer price be C]

Also we know

0.8j = Adrian

We can put this in to get:

A = 1.15C

C = A/1.15

C = 0.8j/1.15

THis is an expression for Corbin's computer price in terms of j:

\frac{0.8j}{1.15}

5 0
3 years ago
30x/53 * 47/15write the product in the simplest form
Talja [164]

47/15 in its simplest form would be 2/15

4 0
3 years ago
How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?
Mrac [35]
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8} 
{2} U {1, 5, 6, 8} 
{5} U {1, 2, 6, 8} 
{6} U {1, 2, 5, 8} 
{8} U {1, 2, 5, 6} 
{1, 2} U {5, 6, 8} 
{1, 5} U {2, 6, 8} 
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6} 
{1, 2, 5} U {6, 8} 
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5} 
The answer is 15 distinct pairs of disjoint non-empty subsets.
5 0
3 years ago
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