Answer:
the empirical formula of the metal fluoride.
Explanation:
Mass of copper heated = 8.249 g
Mass of copper fluoride formed = 13.18 g
Mass of fluorine gas in copper fluoride = x
Moles of copper :
Moles of fluorine:
For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.
The empirical formula of the copper fluoride =
the empirical formula of the metal fluoride.
Answer:
Q = 16163.88 Joules
Explanation:
Given the following data;
Initial temperature, T1 = -25°C
Final temperature, T2 = 150°C
Mass = 45.5 g
Specific heat capacity of ice = 2.03 J/g°C
To find the quantity of heat required;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 150 - (-25)
dt = 150 + 25
dt = 175°C
Substituting into the formula, we have;
Q = 16163.88 Joules