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3 years ago

What does temperature measure?

Chemistry

2 answers:

Schach [20]3 years ago

8 0

Temperature measures the (average) <span>kinetic energy of a system .</span>

lesya [120]3 years ago

7 0

Answer:

Kinetic energy of a system .

Explanation:

Hello,

The temperature is a measure of the average kinetic energy of the atoms or molecules in the system as long as it accounts for the movement of the particles composing the system, thus, the higher the temperature, the higher the kinetic energy as the atoms or molecules could move faster and vigorously.

Best regards.

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3 years ago

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3 years ago

What is the equilibrium expression for the reatcion bellow<br><br> 2SO3(g)<=>O2(g)+2SO2(g)

Luda [366]

Answer:

[O2(g)][SO2(g)]^2/[SO3(g)]^2

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3 years ago

How many protons and electrons are present in Au+?

balandron [24]

Answer:

Protons: 79

Electrons: 78

Explanation:

1. The number of protons is the atomic number (The atomic number for Au on the periodic table is 79)

2. Since the charge is +1 (positive) it means that there's one more proton than electrons. So, 79-1 = 78 electrons

7 0

3 years ago

What is the % composition of Carbon in Chromium (iii) Carbonate

photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

$Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3$

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

$\begin{gathered} C\rightarrow3\times12=36 \\ \\ O\rightarrow9\times16=144 \\ \\ Cr\rightarrow2\times52=104 \end{gathered}$

The molar mass will be thus:

$M=36+104+144=284\text{ g/mol}$

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

$\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\ \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}$

The percent composition of Carbon is thus 12.7 %.

8 0

1 year ago