since the number is going on the opposite it must be a negative integrer.
and since the number was 6 units away from 0, it should be the half point between the points.
number = 3
since it is going in the oppsoite direction it should be -3
V(t)=t^2+2t+1 integrating we get d(t)
d(t)=t^3/3+t^2+t or more neatly
d(t)=(t^3+3t^2+3t)/3 so
d(2)=(8+12+6)/3
d(2)=26/3
So the particle moves 9 feet (to the nearest foot) in the first two minutes.
The answer is x equals the square root of y+1/4
Answer:
4000 yd^2
Step-by-step explanation:
50 yd * 80 yd = (50*80) ( yd * yd) = 4000 yd^2