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SOVA2 [1]
3 years ago
15

What number is halfway between 7/3 and 5/9 ?

Mathematics
2 answers:
Dmitrij [34]3 years ago
5 0

Answer:

The answer is 39/2

Step-by-step explanation:

The explanation is given in the image attached

Eddi Din [679]3 years ago
4 0

    You add the two numbers and divide by two to get their average, of the number that would be midway (also a midpoint for visualization) between them. Find the least common denominator, which should be 9. Thus, you will multiply both the numerator and denominator of 7/3 by 3 to retain the ratio. You should get 21/9. Now, add 21/9 and 5/9 to get 26/9. That should be your answer, but make it a mixed number so you don't have an improper fraction.

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-2 = g - 9 solve equation
jekas [21]

OK.  Hold on tight.  Here we go.
Remember ... the "solution" is the number that 'g' must be
in order to make the equation a true statement.

The original equation:   You said that  -2 = g - 9

Now, let's add  9  to each side:             7 = g .

8 0
3 years ago
Read 2 more answers
Honda Atlas issued 100,000 shares of stock. In 1990, each share of stock was worth Rs. 152.50. In 1993, each share of the stock
noname [10]

Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

No. of stocks issued in 1990 = 100,000

Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990  = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

No. of stocks   1993 = 100,000

Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993  = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

 =  Rs. 15,250,000 - Rs. 2,120,000

 = Rs.13,130 ,000

Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

6 0
3 years ago
How to find the answers ?
maria [59]

AD || BC and BD is the transversal,

Therefore, angle DBC = angle ADB = 42° [alternate angles]

AD || BC and BD is the transversal,

angle BAD + angle ABD + angle DBC = 180° [co-interior angles]

or, 106°+ angle ABD + 42° = 180°

or, 148° + angle ABD = 180°

or, angle ABD = 180°-148° = 32°

Therefore, angle ABC = (32+42)° = 74°

AB||CD and BC is the transversal,

angle ABC + angle BCD = 180° [co-interior angles]

or, 72+2x+12 = 180

or, 84+2x = 180

or, 2x=180-84 = 96

or, x = 48

Answers: a)48°

b)42°

c)72°

3 0
2 years ago
2/9 - 1/5 • x write an equivalent expression
Bas_tet [7]

Answer:

1/45

Step-by-step explanation:

6 0
3 years ago
Select the correct answer from each drop-down menu.
Ivahew [28]

In 20 minutes, John can wrap 10 small boxes and Hank can wrap 12 small boxes. So, Hank can wrap more small boxes in 20 minutes than John can.

Step-by-step explanation:

Given,

John wraps;

2 small boxes = 4 minutes

1 small box = \frac{4}{2} = 2\ minutes

In 20 minutes,

20 minutes = \frac{Total\ time}{Time per box} = \frac{20}{2}

20 minutes = 10 small boxes

Hank wraps;

3 small boxes = 5 minutes

1 small box =\frac{5}{3}\ minutes

In 20 minutes = \frac{Total\ time}{Time per box} = \frac{20}{5/3}

20\ minutes=\frac{20*3}{5}\\20\ minutes=\frac{60}{5}\\20\ minutes= 12\ small\ boxes\\

In 20 minutes, John can wrap 10 small boxes and Hank can wrap 12 small boxes. So, Hank can wrap more small boxes in 20 minutes than John can.

Keywords: division, multiplication

Learn more about division at:

  • brainly.com/question/1836777
  • brainly.com/question/2115122

#LearnwithBrainly

8 0
3 years ago
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