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liubo4ka [24]
4 years ago
7

Which of the following is NOT possible? A = A triangle where one angle measures 20 degrees and another angle measures 45 degrees

. B = A triangle where one angle measures 120 degrees and another angle measures 50 degrees. C = A triangle where one angle measures 90 degrees and another measures 100 degrees. D = A triangle were one angle measures 67 degrees and another measures 67 degrees. Group of answer choices B C A D
Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
5 0

Answer:

C

Step-by-step explanation:

the angle measures of triangles must add up to 180 degrees. Since we are only given two angles, we can assume that all of the answers that add up to be below 180 degrees fulfill this requirement with the third angle. However, answer choice C adds up to 190 degrees on the first two angle, which means that no matter how low the third angle is, it will never add up to 180 degrees.

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B

Step-by-step explanation:

Domain is basically x. The left side is connecting with the right side (y).

this is why the domain is B

Hope this helps!

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3 years ago
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R- (-12.4) = -15.8<br><br>A. -3.4<br>B. -28.2<br>C. 3.4<br>D. 28.2​
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Answer:

The answer is B.

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Problem Page At a certain college, 49% of the students are female, and 19% of the students major in civil engineering. Furthermo
SIZIF [17.4K]

Answer with Step-by-step explanation:

Let

A=Students are female

B=Students major in civil engineering

The probability that a students are female=P(A)=\frac{49}{100}=0.49

The probability that a student major in civil engineering=P(B)=\frac{19}{100}=0.19

The probability that students both are female=P(A\cap B)=\frac{12}{100}=0.12

a.We have to find the probability that a random selected female student major in civil engineering.

We have to find P(B/A)

P(B/A)=\frac{P(A\cap B)}{P(A)}

P(B/A)=\frac{0.12}{0.49}=0.24

Hence, the probability that a randomly selected female student majors in civil engineering=0.24

b.We have to find the probability that a random selected civil engineering major is female.

We have to find P(A/B)

P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0.12}{0.19}=0.63

Hence, the probability that a randomly selected civil engineering major is female=0.63

3 0
3 years ago
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Answer:

Step-by-step explanation:

Replace W with 2

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which your answer in the end would be 12 = 12

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4 years ago
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