Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
Answer:
<u>We observe that this is a GP with:</u>
- the first term t₁ = 5
- common ratio r = -2
<u>The nth term is:</u>
21/16 which simplifies to 1 and 5/16
You get this by making 1 1/2 a mixed number (3/2). To get 3/2 you do: bottom times the side plus the top---2x1=2+1=3. So 3/2
Then you multiply across:
7x3=21
8x2=16
So 21/16 is your answer
Whenever you move from the left to right or right to left of any linear equations, you have to switch from plus to minus or multiply to division.
Answer:
NP NP
Step-by-step explanation:
this is the only solution that works for the question