Answer:
The answer to your question is empirical formula = CH
molecular formula = C₆H₆
Explanation:
Data
Carbon 92.2%
Hydrogen 7.76%
Formula mass = 78.1 g
Process
1.- Express the percents as grams
Carbon 92.2 g
Hydrogen 7.76 g
2.- Convert the grams to moles
Carbon 12 g ---------------- 1 mol
92.2 g ------------- x
x = (92.2 x 1)/12
x = 7.68 moles
Hydrogen 1 g ------------------ 1 mol
7.76 g ------------- x
x = 7.76 moles
3.- Divide by the lowest number of moles
Carbon 7.68 / 7.68 = 1
Hydrogen 7.76 / 7.68 = 1.01
4.- Write the empirical formula
CH
5.- Calculate the molecular weight of the empirical formula
CH = 12 + 1 = 13
6.- Divide the molecular weight by the molecular weight of the empirical formula
78.1 / 13 = 6
7.- Write the molecular formula
6(CH) = C₆H₆
Answer:
Explanation:
First thing is we have assume all the percents are grams so we have
68.279g C, 6.2760g H, 3.7898g N, and 21.656g O
Now convert each gram to moles by dividing the the molar mass of each element
68.279g/12.01g= 5.685 moles of C
6.2760g/1.01g= 6.214 moles of H
3.7898g N/14.01g= 0.271 moles of N
21.656g O/ 16.00g= 1.354 moles of O
Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....
5.685 moles/0.271 moles ------> ~21 C
6.214 moles/0.271 moles --------> ~23 H
0.271 moles / 0.271 moles ---------> 1 N
1.354 moles/ 0.271 moles ----------> ~5 O
So the empirical formula is C21H23NO5
CuSO4 + Zn(NO3)2 > Cu(NO3)2 + ZnSO4