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aivan3 [116]
3 years ago
10

How many grams will be produced

Chemistry
1 answer:
Anni [7]3 years ago
4 0

Answer:

\Large \boxed{\sf 34.2 \ g}

Explanation:

Mole ratio

9:4

1.75:x

Moles of CO₂

\displaystyle \frac{4 \times 1.75}{9} =0.78

Use formula to find mass

\displaystyle moles=\frac{mass}{M_r}

Relative molecular mass of CO₂ = 12 + 16 × 2 = 44

\displaystyle 0.78=\frac{mass}{44}

mass=34.2

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Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
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