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3 years ago

How many grams will be produced

Chemistry

1 answer:

Anni [7]3 years ago

4 0

Answer:

$\Large \boxed{\sf 34.2 \ g}$

Explanation:

Mole ratio

$9:4$

$1.75:x$

Moles of CO₂

$\displaystyle \frac{4 \times 1.75}{9} =0.78$

Use formula to find mass

$\displaystyle moles=\frac{mass}{M_r}$

Relative molecular mass of CO₂ = 12 + 16 × 2 = 44

$\displaystyle 0.78=\frac{mass}{44}$

$mass=34.2$

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When salt is added to water, the entropy, S,

Dovator [93]

Answer:

C. number of particles

Explanation:

Entropy is the measure of disorderliness of a system. Remember that when you dissolve salt in water, you increase the number of particles in the solution. The greater the number of particles in solution, the greater the entropy of the solution system.

Hence dissolution of a salt in water increases the entropy by increasing the number of particles in solution leading to the inequality; Ssolution > Swater + Ssalt.

5 0

3 years ago

Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

$Density= \frac{Mass}{Volume}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

3 0

3 years ago

Basis for all living things; every living thing contains this element

kirza4 [7]

Answer:

Carbon

Explanation:

Carbon is the primary component of macromolecules, including proteins, lipids, nucleic acids, and carbohydrates.

6 0

3 years ago

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A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o

Andre45 [30]

Answer:

* $x_{CH_3OH}=0.0425$

* $\%m/m_{CH_3OH}=7.31\%$

* $m=2.46m$

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

$x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}$

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

$n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O$

Hence, mole fraction is:

$x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425$

Next, mass percent is:

$\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%$

And the molality, considering the mass of water in kg (0.185 kg):

$m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m$

Regards.

7 0

3 years ago

The wavelength of light is 310. nm; calculate the frequency.

kondor19780726 [428]

Frequency = velocity of propagation / wavelength.

<span>For light, we assume it is moving in a vacuum, so vp is 3e8 m/s. The wavelength of 310nm is 310e-9 meters. Then we plug the numbers in, and we get (3e8 m/s) / (310e-9 m) = 967.742e12 Hz because 1/s is the same as cycles/sec, which is a Hertz.</span>

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4 years ago

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