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Verdich [7]
3 years ago
12

What is the ratio of 3400 and 8579

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0
5179-8579 is the answer and you'll see why, the ration is the difference between two numbers and in which you would call the following number on the right, shown as 8579
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Determine the center and radius of the following circle equation:<br> x2 + y2 – 10x + 8y + 40 = 0
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Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

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