x + y = 3
- x - x
y = -x + 3
y - y₁ = m(x - x₁)
y - (-1) = -1[x - (-1)]
y + 1 = -1(x + 1)
y + 1 = -1(x) - 1(1)
y + 1 = -x - 1
- 1 - 1
y = -x - 2
The answer is B.
Answer:
Step-by-step explanation:
The co-ordinates of the rectangle are:
A (8, 6)
B (-4, -10)
C (-8, -7)
D (4, 9)
The Area of Rectangle is Given by: <em>length x breadth </em>= AB x BC
Lengths of AB and BC can be found by distance formula
<em>length</em>(AB) =
= 
Similarly,
<em>length</em>(BC) = 5
Area of Rectangle = AB x BC = 20 x 5 = 100 square units
<span>2 square root (x - 5) = 2. 2^2 (x -5) = 2^2. 4(x - 5) = 4. 4x - 20 = 4. 4x = 24. x = 6. This solution is not extraneous, because extraneous solutions emerge from solving the problem but are not actually valid solutions for the initial problem. With rounding, this solution is valid for the initial problem.</span>
Answer:
Therefore the required resulting equation is

6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
Step-by-step explanation:
Given:
......................Equation ( 1 )
......................Equation ( 2 )
To Find:
Expression after multiplying to eliminate y term,
Solution:
So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5, such that equations becomes
.....( 1 )
.....( 2 )
so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,
Therefore the required resulting equation is

6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
Answer:idk help
Step-by-step explanation: