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3 years ago

PLZ HELP I'M IN A TEST (will give brainliest)

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

7 0

Answer:

The correct answer is C

Step-by-step explanation:

The height of the original triangle is 3 and the length is 6, so we have a ratio of 3:6. The only triangle that works is the one with a height of 5 and a length of 10 because both simplify to 1:2.

Hope this helped!

const2013 [10]3 years ago

7 0

Answer:

it is c i just took the quiz and passed

Step-by-step explanation:

The height of the original triangle is 3 and the length is 6, so we have a ratio of 3:6. The only triangle that works is the one with a height of 5 and a length of 10 because both simplify to 1:2.

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2b - 3 / 3 (fraction) - 5 = 10. <br> Solve for B

Shkiper50 [21]

Answer:

Step-by-step explanation:

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3 years ago

Triangle ABC has vertices A( -3, 5) B ( 6, 9) and C ( -4, - 12) in the coordinate plane. The triangle is reflected over the x- a

hichkok12 [17]

Answer:

The coordinates of triangle A"B"C" will become

A( 5,-3 ) B( 9,6 ) C( -12 ,-4 )

Step-by-step explanation:

Original vertices of triangle ABC are ;

A ( -3, 5 ) B( 6, 9 ) C ( -4, -12 )

after reflection over x-axis

A( -3,-5 ) B( 6, -9 ) C( -4,12 )

when the triangle is rotated

x coordinates becomes -y while y coordinates becomes x

The coordinates of triangle A"B"C" will become

A( 5,-3 ) B( 9,6 ) C( -12 ,-4 )

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3 years ago

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cestrela7 [59]

d i believe so it might be d if not i’m sorry

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3 years ago

4. Find the volume of a square pyramid with a base length of 9 cm and a height of 4 cm (1 point)

Bond [772]

I think it’s 48 but are those the only answer choices???

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3 years ago

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Two bicyclists leave the center of town at the same time. One heads due north and the other heads due west. Later, the two cycli

Ad libitum [116K]

This situation is represented in annex.
From Pythagorean theorem you've got equation:
$x^2+(x+5)^2=25 \\ \\ \hbox{From formula} \ \ \ (a+b)^2 = a^2+2ab+b^2: \\ \\ x^2+x^2+10x+25=25 \\ 2x^2+10x=0 \\ \\ \hbox{Factor out} \ \ 2x: \\ 2x(x+5)=0 \\ \\ \hbox{So you've got:} \\ \\ x_1=0 \\ x_2=-5$

There isn't any solutions where x>0, so this situation is IMPOSSIBLE.

Did you write correctly this question....?

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3 years ago

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