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3 years ago

The question say determine k what does it mean by k?

Mathematics

1 answer:

kherson [118]3 years ago

5 0

Answer:

k means the equation

Step-by-step explanation:

as u put 10 and 60 that would mean k= times 6 if all of them you have to multiply by 6

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Solve each system by elimination.

strojnjashka [21]

Answer:

y = -1, x = -2

Step-by-step explanation:

First, multiply the top equation by 2 to make 3x become 6x:

6x - 8y = -4

Second, multiply the bottom equation by 3 to make -2x become -6x:

9y - 6x = 3

Add the two equations together, and you get:

y = -1

Plug in y as -1 into the first or second equation:

3x - 4(-1) = -2

3(-1) - 2x = 1

x = -2

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Step-by-step explanation:

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ziro4ka [17]

Answer:

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Step-by-step explanation:

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3 years ago

Express p in terms of q if

Irina-Kira [14]

$p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)$

$q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}$

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3 years ago