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docker41 [41]
3 years ago
9

HELP???? ASAP!!! HELP????

Mathematics
2 answers:
KengaRu [80]3 years ago
7 0
I think that its C........
ahrayia [7]3 years ago
5 0
It's definitely B because she added 15.6 and 29.07
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Find the general form, Ax2+Ay2+Dx+Ey+F=0, by identifying the coefficients A,D,E,&F center:(0,1); r=1 (x-0)2+(y-1)2=1 x2+y2-2
siniylev [52]

Answer:

The value of A is 1, D is 0, E is -2 and F is 0.

Step-by-step explanation:

The given equation is

Ax^2+Ay^2+Dx+Ey+F=0             ...(1)

The standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius.

(x-0)^2+(y-1)^2=1

x^2+y^2-2y+1-1=0

x^2+y^2-2y=0

It can be written as

x^2+y^2+0x-2y+0=0                          ....(2)

On comparing (1) and (2) we get.

A=1

D=0

E=-2

F=0

Therefore the value of A is 1, D is 0, E is -2 and F is 0.

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4 years ago
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Please help me !!! A question for Pre- Calculus Conic Sections!
8090 [49]
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A classmate wrote the solution to the inequality |-4x + 1| > 3 as show below. Describe and correct the error.
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Answer:

See below.

Step-by-step explanation:

The last step is incorrect. When we divide both sides by a negative the inequality is flipped. The answer is x < -1/2.

Also they  omitted  the other possibility that the expression in the vertical lines could be negative.

We also have the inequality

- 4x + 1 < - 3

-4x < -4

x > 1.

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22 percent
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3 years ago
14x − 5 − 8x = 1 A) 0 B) 1 C) 3 D) 5
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