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3 years ago

Solve 3(x + 2) > x.

Mathematics

2 answers:

valkas [14]3 years ago

8 0

Answer:

x > -3

Step-by-step explanation:

Kamila [148]3 years ago

6 0

Answer:

3x + 6 > x

2x > -6

x > -3

answer is d

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If you need $3,000 four years from now, how much would you need to deposit into an account that earns 5% interest, compounded an

Aleks04 [339]

Answer:

2468.11 dollars

Step-by-step explanation:

Amount that should be available after four years =3000 $

Interest rate = 5%

No of years =4

Let P be the principal invested

Then $3000=P(1+0.05)^4\\P=3000(1.05)^{-4} \\=2468.11$

Hence 2468.11 dollars should be deposited to get 3000 dollars after 4 years at 5% interest.

6 0

2 years ago

Can somebody answer this ? : n-4-9

FinnZ [79.3K]

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

n - 13

Subtract 9 from -4

Hope it helps.

Have a nice day noona/hyung!~ ￣▽￣❤️

4 0

2 years ago

Helppppp on alllll plz

igomit [66]

a. $150

b. 150+20x $\geq$ 630

20x $\geq$ 480

x $\geq$ 24

c. 150+20x $\geq$ 750

20x $\geq$ 600

x $\geq$ 30

d. 150+20x $\leq$ 950

20x $\leq$ 800

x $\leq$ 40

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

3 0

2 years ago

Simplify 5(x+3) -9x+4

laiz [17]

Answer:

$=5x+15-9x+4\\=-4x+19\\$

5 0

2 years ago

Read 2 more answers

2v^2-12 =-12v <br> Would really appreciate it loves❤️

Black_prince [1.1K]

For this case we have the following equation:

$2v ^ 2-12 = -12v$

Rewriting we have:

$2v ^ 2 + 12v-12 = 0$

Dividing by 2 to both sides of the equation:

$v ^ 2 + 6v-6 = 0$

We apply the quadratic formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have to:

$a = 1\\b = 6\\c = -6$

Substituting:

$x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}$

Thus, we have two roots:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

ANswer:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

7 0

2 years ago