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poizon [28]
3 years ago
7

What is the center of the circle? Also, use the midpoint formula to verify it.

Mathematics
1 answer:
il63 [147K]3 years ago
5 0

Answer:

center : (-2, -2.5)

Step-by-step explanation:

Midpoint point formula says that if there are two points (x1,y1) and (x2,y2) then

coordinate of midpoint is given by

midpoint (x1+x2)/2 , (y1+y2)/2

_______________________________________________

In the problem, we have to find the center of circle of by using the midpoint formula.

Since the circle is circumscribed in square. Its center will be midpoint of either of the diagonal.

To find the center we can take coordinate of any of two diagonal points of square and find midpoint for this and that will be center of circle.

_________________________________________________

1st diagonal pair(4,8) and (-8,-3)

Then midpoint is (4 + -8)/2 , (8+ -3)/2  

midpoint (-2, -2.5)

Thus, center of circle is (-2,-2.5)

we can verify this by using other diagonal pair (-8,8) and (4,-3)

Midpoint in this case can be calculated as

midpoint (-8+4)/2 , (8 + -3)/2

midpoint (-2,-2.5)

Thus, we see that in both cases Midpoint is same and hence center is (-2, -2.5)

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Step-by-step explanation:

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Let X be the width of the path.

The width of the path would be the width of the pool plus 2x, so 2x +16

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Area is found by multiplying the length by the width.

So you have:

(2x+16) (2x+22) = 832

Use the Foil Method:

(2x+16) (2x+22) = 4x^2 +76x+352

Now you have:

4x^2 +76x+352 = 832

Subtract 832 from both sides:

4x^2 +76x+352-832 = 0

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4x^2 +76x -480

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Answer:

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Step-by-step explanation:

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y+8-8=\frac{-1}{2}\left(x-4\right)-8

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