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Bond [772]
3 years ago
15

There are moles in 1.26 × 1024 particles.

Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

1.26 x 10^(24)

Step-by-step explanation:

hope this helped

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2 years ago
A particular computer takes 11 minutes to download a 33​-minute TV show. How long will it take the computer to download a 2.5​-h
zhenek [66]

First off.. we need to get the units the same.  All in hours,

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12 minutes = 12/60 hours = 1/5 hours = 0.2 hours

Set up a proportion:

0.2 is to 0.6 as x is to 22.5

x/22.5 = 0.2/0.6

x = 0.2(22.5)/0.6

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8 0
3 years ago
2, 10 after a dilation by a scale factor of 1/2 centered at the<br> origin?
anzhelika [568]

Answer:

  (1, 5)

Step-by-step explanation:

When the center is the origin, the dilation factor multiplies each coordinate:

  (2, 10) ⇒ (1/2)(2, 10) = (1, 5)

3 0
2 years ago
Given that 2x + 1 =5, what is the value of (x+3)^3
Alla [95]

Answer: 125

Step-by-step explanation:

First, solve for x in the first equation.

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2x = 4

2) Divide by 2 on both sides.

x = 2

Next, substitute the value of x into the second expression.

(2 + 3)^3

= 5^3

= 125

5 0
3 years ago
Read 2 more answers
Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
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