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3 years ago

8

PLS HELP RN! If a translation maps ∠E onto ∠A, which of the following statements is true?

1 answer:

melisa1 [442]3 years ago

8 0

Answer:

The answer is ∠B ≅ ∠D

Step-by-step explanation:

I took the test and got it right, but you can just use the triangle sum theorem to know that when you have two angles of a triangle, you automatically know the third angle is the same.

You can also see this in AA similarity postulate as all you need to know is two angles to know if it is a similar triangle!

Hope this helps!

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Joshua has $4,200 to invest for college. If Joshua invests $4,200 for 3 years and earns $630, what is the simple interest rate?

Rama09 [41]

Answer:

The simple interest rate is 5%.

This is possible with a rate of 6%, since in this case, his amount earned will be $5,208.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

$T = E + P$

Joshua has $4,200 to invest for college. If Joshua invests $4,200 for 3 years and earns $630, what is the simple interest rate?

We have that $P = 4200, E = 630, t = 3$ . We have to find I.

$E = P*I*t$

$630 = 4200*I*3$

$I = \frac{630}{4200*3}$

$I = 0.05$

The simple interest rate is 5%.

Joshua’s goal is to have $5,000 after 4 years. Is this possible if he invests with a rate of return of 6%?

We have to find T when $P = 4200, t = 4, I = 0.06$

So

$E = P*I*t$

$E = 4200*0.06*4$

$E = 1008$

$T = E + P = 4200 + 1008 = 5208$

This is possible with a rate of 6%, since in this case, his amount earned will be $5,208.

7 0

3 years ago

The per capita growth rate of many species varies temporally for a variety of reasons, including seasonality and habitat destruc

Veronika [31]

Answer:

$n(t)=n_0e^{(1-e^{-t }-t)}$

Step-by-step explanation:

If n(t) represents the population size at time t, where n is measured in individuals and t is measured in years.

$\frac{dn}{dt}=n(e^{-t }-1), n(0)=n_o$

$\frac{dn}{n}=(e^{-t }-1)dt$

Taking the integral of both sides

$\int\frac{dn}{n}=\int(e^{-t }-1)dt\\\int\frac{dn}{n}= \int e^{-t }dt-\int1dt$

ln |n| = $-e^{-t }-t+C$

Where C is integration constant

Taking the exponential of both sides

$n=e^{(-e^{-t }-t+C)}$

$n=e^{(-e^{-t }-t)}e^C\\n=Ke^{(-e^{-t }-t)}$ whee the exponential of a constant is a constant K.

When t=0, $n(0)=n_o$

$n_0=Ke^{-1$

Therefore:

$n=n_0e^{1}e^{(-e^{-t }-t)}$

$n(t)=n_0e^{(1-e^{-t }-t)}$

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3 years ago

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natima [27]

The answer is not in the multiple choice options, but I believe the correct answer is x > -0.2

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3 years ago

What are the zeros on the function represented by the qudratic expression 2x^2-5x-3 Show work please

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y=2x^2-5x-3=(x-3)(2x+1)

supposey=0

x=3 or x= -1/2

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3 years ago

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o-na [289]

B step by step hope this helps

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3 years ago