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liq [111]
3 years ago
13

What is the answer to 9 and 10??? Only if you know please i will report you no games

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer:

9) X = 108

10) X = 180 - 134 =46

Step-by-step explanation:

jok3333 [9.3K]3 years ago
6 0

Answer:

10 answer is 46

Step-by-step explanation:

and 9 answer is108

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Given the inequality -8 < 2, explain what happens when you multiply or divide both sides by 2 and what happens when you multi
Gnoma [55]

Answer:

The inequality sign remains same while multiply or divide both sides by positive numbers.

The inequality sign changes while multiply or divide both sides by negative numbers.

Step-by-step explanation:

The given inequality is - 8 < 2.

Now, if we multiply 2 in both sides then - 16 < 4

Again, if we divide by 2 into both sides then  - 4 < 1

Therefore, the inequality sign remains the same while multiply or divide both sides by positive numbers.

Now, if we multiply -2 in both sides then 16 > -4

And, if we divide -2 into both sides then 4 > -1

Therefore, the inequality sign changes while multiply or divide both sides by negative numbers. (Answer)

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3 years ago
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The perimeter of a square P depends on the length of its sides S this can be written in function notation as P( s) what is the b
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Answer:

Step-by-step explanation:

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2 years ago
Set up an equation and use it to solve for X<br> (6x + 3)<br> 33°
Elodia [21]

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Step-by-step explanation:

The angles of a linear pair are supplementary.

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3 years ago
PLEASE HELP QUICK! DID I PUT THE RIGHT ANSWER FOR QUESTION 13
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Answer:

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Step-by-step explanation:

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3 years ago
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Air is being pumped into a spherical balloon at a rate of 5 cm^3/min. Determine the rate at which the radius of the balloon is i
Romashka-Z-Leto [24]

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Step-by-step explanation:

Given:

\dfrac{dV}{dt}=5\:\text{cm}^3\text{/min}

Find \frac{dr}{dt} when diameter D = 20 cm.

We know that the volume of a sphere is given by

V = \dfrac{4\pi}{3}r^3

Taking the time derivative of V, we get

\dfrac{dV}{dt} = 4\pi r^2\dfrac{dr}{dt} = 4\pi\left(\dfrac{D}{2}\right)^2\dfrac{dr}{dt} = \pi D^2\dfrac{dr}{dt}

Solving for \frac{dr}{dt}, we get

\dfrac{dr}{dt} = \left(\dfrac{1}{\pi D^2}\right)\dfrac{dV}{dt} = \dfrac{1}{\pi(20\:\text{cm}^2)}(5\:\text{cm}^3\text{/min})

\:\:\:\:\:\:\:= 0.08\:\text{cm/min}

3 0
3 years ago
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