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Mariulka [41]
3 years ago
6

The Wongs are putting a flagstone deck around their pool. The pool is rectangular. Its dimensions are 8 m by 4 m. The deck will

surround the pool. It will have a width of 2 m. What is the area of the deck?
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer: 64 i believe

Hope this helps :)

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48 times a number of game markers, g
Aleksandr-060686 [28]

Answer: 48g

Step-by-step explanation:

All you are doing is multiplying the number of game markers, forty-eight times, so you can write your answer as, 48g.

5 0
3 years ago
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What do you get when you evaluate (-1) 50?
RoseWind [281]

Answer:--50

Step-by-step explanation:

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What’s the answer to this
Virty [35]

Answer:

x=20

Step-by-step explanation:

Look Angle A and D are Congruent so they equal the same

3x−10=2x+10

Subtract 2x from both sides

3x−10−2x=2x+10−2x

x−10=10

Add 10 to both sides.

x−10+10=10+10

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Hope This helps

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3 years ago
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Identify the interval(s) on which the function y = 2x^2 - 8x - 10 is positive.
Serga [27]

Given:

y=2x^2-8x-10

To find:

The interval(s) on which the given function is positive.

Solution:

We have,

y=2x^2-8x-10

y=2(x^2-4x-5)

y=2(x^2-5x+x-5)

y=2(x(x-5)+1(x-5))

y=2(x+1)(x-5)

For zeroes, y=0

2(x+1)(x-5)=0

x=-1,x=5

-1 and 5 divide the number line in three parts (-\infty , -1),(-1,5),(5,\infty ).

Interval        Selected Value      y=2(x+1)(x-5)                      Sign

(-\infty,-1)                -2                  y=2(-2+1)(-2-5)=14           +

(-1,5)                     0                   y=2(0+1)(0-5)=-10              -

(5,\infty)                       6                  y=2(6+1)(6-5)=14                 +

So, the function is positive for interval (-\infty,-1) and (5,\infty).

We can say that the function is positive for interval x < -1 and x > 5.

Therefore, the correct option is B.

8 0
3 years ago
Select the angle whose sine equals 12/37
Mazyrski [523]

Answer:

r

Step-by-step explanation:

sin is o/h so across from 12 would be the angle r

6 0
3 years ago
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