The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
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I don't understand what you want solved for here...could you please tell me?
Answer:
The answer to the problem is J
1a. 21/3+32/5
((2*3)+1)/3+((3*5)+2)/5
7/3+17/5
(7*5+17*3)/15
86/15
1b. 2/3+3/5+2/5
(2*5+3*3+2*3)/15
(10+9+6)/15
25/15
5/3
2a. 57/10-22/5
(5*10+7)/10-(2*5+2)/5
57/10-12/5
(57*1-2*12)/10
33/10
2b. 5/12-1/4
(5*1-1*3)/12
2/12
1/6
3 say she has x stamps,she gave 2/9 and 1/5 to her frends so she is left with
X-2x/9-x/5
(9*5x-5*2x-9*1x)/45
(45x-10x-9x)/45
26x/45
4. 7/10+1/5
(1*7+2*1)/10
9/10
5. Brick 21/3kg
Stone (2*3+1)/3-(1*10+1)/10
7/3-11/10
(7*10-3*11)/30
(70-33)/30
37/30
