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valkas [14]
3 years ago
12

Give the equation of the line that passes through the points (4,6) and (-2,3)

Mathematics
2 answers:
loris [4]3 years ago
8 0

Answer:

D. y = 1/2x + 4

Step-by-step explanation:

Slope: (6-3)/(4--2) = 3/6 = 1/2

y = ½x + c

6 = ½(4) + c

6 = 2 + c

c = 4

y = ½x + 4

Nutka1998 [239]3 years ago
3 0

Answer:

y = 1/2x+4

Step-by-step explanation:

First we find the slope

m = (y2-y1)/(x2-x1)

    = (3-6)/(-2-4)

    = -3/-6

   =1/2

The equation of a line in slope intercept form is

y = mx+b  where m is the slope and b is the y intercept

y =1/2x+b

Substitute one of the point into the equation

6 = 1/2(4) +b

6 = 2+b

b=4

y = 1/2x+4

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bogdanovich [222]
The result is -6 
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Please please solve the whole page please
marishachu [46]

Answer:

Step-by-step explanation:

1. 94/100=0.94=94%

2.15/20=0.75=75%

3. 4/10=0.4=40%

4. 3/100=x/100 》x=3

5. 80/100=x/30 》x=2400/100=24

6. 30/100=x/10 》x=3

7. 2/5=0.4=40%

8. 60/100=x/5 》 x=300/100=3

9. 50/100*x=150 》 50x=15000 》x=300

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7 0
1 year ago
A tentmaker has 60,000 tents in stock. The Army decides to order 200 tents
Nastasia [14]

Answer:

300

Step-by-step explanation:

60,000 / 200 = 300

7 0
3 years ago
A survey of an urban university (population of 25,450) showed that 870 of 1,100 students sampled supported a fee increase to fun
Katen [24]

Answer:

95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C

Step-by-step explanation:

The confidence interval for a proportion is given as [p +/- margin of error (E)]

p is sample proportion = 870/1,100 = 0.791

n is sample size = 1,100

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (z) at 5% significance level is 1.96.

E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024

Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767

Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815

95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.

5 0
2 years ago
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