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3 years ago

8

Is a linear model or a quadratic model a better fit

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

Quadratic

Step-by-step explanation:

Linear equations are straight lines while quadratics are curved in a "u" shape. These points have a vertex and go up on both sides, a quadratic would be able to better fit this since their y values repeat, unlike linear models.

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The number of pieces of dog food in a one-cup scoop is approximately Normally distributed with a mean of 205 pieces and a standa

Nastasia [14]

It’s C because you are just the best

8 0

3 years ago

ankoles [38]

We subtract the 17 from the 981 to make the two sides even so it’s easier to calculate, 981 - 17 = 964, then divide that by 2, 964/2 = 482. So your answer is 482.

Would appreciate brainliest!

6 0

2 years ago

What is y={-\dfrac{1}{3}}x-9y=− 3 1 x−9y, equals, minus, start fraction, 1, divided by, 3, end fraction, x, minus, 9 written i

Kobotan [32]

Answer:

$x+3y=-27$

Step-by-step explanation:

We are given that

$y=(-\frac{1}{3})x-9$

We have to find the standard form of given equation

$y=\frac{-x-27}{3}$

$3y=-x-27$

By using multiplication property of equality

$x+3y=-27$

We know that

Standard form of equation

$ax+by=c$

Therefore, the standard form of given equation is given by

$x+3y=-27$

5 0

3 years ago

Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de

Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

$H_0: \mu=7\\\\H_a:\mu> 7$

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25$

The degrees of freedom for this sample size are:

$df=n-1=49-1=48$

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t>5.25)=0.000002$

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0

3 years ago

Need Help, Trying To Finish .

hammer [34]

Answer:

8

Steps:

Plug in 2 for x in h(x)

h(2) = -(2)^2 + 6 * 2

h(2) = -4 + 12

h(2) = 8

3 0

3 years ago