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Firdavs [7]
3 years ago
15

Please help.. I will give points

Mathematics
2 answers:
OleMash [197]3 years ago
6 0

Let us check each option

A. 8^{9/2}  and   (\sqrt{8})^{9}

these are equivalent

B. (\sqrt[3]{125} )^9  and     125^{9/3}

these are equivalent

C. 12^{2/7} and (\sqrt{12})^7

these are not equivalent

D. 4^{1/5}  and  (\sqrt{4})^5

these are not equivalent

Daniel [21]3 years ago
4 0

A. 8^9/2= around 11585.2375; (sqrt8)^9= around 11585.2375. So choice A shows a pair of equivalent expressions.

B. (3sqrt125)^9=1,953,125; 125^9/3=1,953,125. So choice B also shows a pair of equivalent expressions.

C. 12^2/7= around 2.03394; (sqrt12)^7= around 5,985.96759. So choice C does not show a pair of equivalent expressions.

D. 4^1/5=around 1.31951; (sqrt4)^5=32. So choice D also doesn't show a pair of equivalent expressions.

Your answers are A and B.

I hope this helps ;)

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Find the dimensions of the rectangle with area 256 square inches that has minimum perimeter, and then find the minimum perimeter
mezya [45]

Answer:

Dimensions: A=a\cdot b=256

Perimiter: P=2a+2b

Minimum perimeter: [16,16]

Step-by-step explanation:

This is a problem of optimization with constraints.

We can define the rectangle with two sides of size "a" and two sides of size "b".

The area of the rectangle can be defined then as:

A=a\cdot b=256

This is the constraint.

To simplify and as we have only one constraint and two variables, we can express a in function of b as:

b=\frac{256}{a}

The function we want to optimize is the diameter.

We can express the diameter as:

P=2a+2b=2a+2*\frac{256}{a}

To optimize we can derive the function and equal to zero.

dP/da=2+2\cdot (-1)\cdot\frac{256}{a^2}=0\\\\\frac{512}{a^2}=2\\\\a=\sqrt{512/2}= \sqrt {256} =16\\\\b=256/a=256/16=16

The minimum perimiter happens when both sides are of size 16 (a square).

4 0
3 years ago
What is the length of the unknown side of the right triangle?
DerKrebs [107]

Answer:

13

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem

a^2+b^2=c^2

where<em> a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.

We know that the legs are 5 and 12. We also know the hypotenuse is x, or unknown.

Substitute 5 in for <em>a</em>, 12 for <em>b, </em>and x for <em>c.</em>

<em />5^2+12^2=x^2<em />

Evaluate the exponents.

5^2 is the same as 5*5, which is 25.

12^2 is the same as 12*12, which is 144.

25+144=x^2

Add 25 and 144

169=x^2

We are trying to find out what <em>x</em> is. In order to do this, we have to get <em>x</em> alone. Since x is being squared, take the square root of both sides. The exponent and square root will cancel, leaving x by itself.

\sqrt{169} =\sqrt{x^2} \\\\\sqrt{169}=x\\13=x

The hypotenuse is 13.

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