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RUDIKE [14]
3 years ago
10

Solve the equation using the quadratic formula -x^2+27=6x

Mathematics
2 answers:
san4es73 [151]3 years ago
8 0

-x^{2}+27=6x\\-x^{2}-6x+27=0

Quadratic formula

\frac{-(-1)±\sqrt{6^{2}-4(-1)(27)}}{2(1)}

\frac{1±\sqrt{36+108}}{2}

\frac{1±\sqrt{144}}{2}

\frac{1±12}{2}

\frac{1+12}{2}=\frac{13}{2}=6.5\\\\\frac{1-12}{2}=\frac{11}{2}=-5.5

6.5 or -5.5

MrMuchimi3 years ago
7 0

The answer is:

X= -9, 3

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Twice the difference of a number and six is the same as twelve . Write into algebraic equation
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Answer:

2(n-6)=12

(I went too far in my explanation; I'm not going to erase it because I think it is important to have an example on solving these)

Step-by-step explanation:

Twice the difference of a number and 6 is the same as 12.

Twice means 2 times

Difference means the result of subtracting something.

is the same as means equal to (=).

So we are given 2(n-6)=12.

You can start by dividing 2 on both sides are distributing 2 to terms in the ( ).

I will do it both ways and you can pick your favorite.

2(n-6)=12

Divide both sides by 2.

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Add 6 on both sides

 n     =12

OR!

2(n-6)=12

Distribute 2 to both terms in the ( )

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Add 12 on both sides

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Step-by-step explanation:

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4 0
3 years ago
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