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3 years ago

The sum of 5 times a number and 4 is equal to 6

Mathematics

1 answer:

g100num [7]3 years ago

7 0

Answer:

5(x+4)=6

5 times a number and (+) 4 is equal to 6.

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Which counter example shows that the following is false? Every perfect square has exactly three factors

pshichka [43]

36 is a perfect square, but its factors include 1 and 36, 6 and 6, 4 and 9, 3 and 12, and 2 and 18. that's 9 factors, not 3.

4 0

3 years ago

Dalton when to high school at 11 yrs and 3 months he left high school at 18 yrs and 2 months old how long did Dalton spend in hi

Tanya [424]

Answer:

Dalton spent 6 years and 11 months in high school.

Step-by-step explanation:

Dalton were in high school at the age = 11 years and 3 months He left high school at the age = 18 years and 2 months

Time spent by Dalton in high school = 18 years 2 months - 11 years and 3 months

= (18 - 11) years and (2 - 3) months

= 7 years - 1 month

= (6 + 1) years - 1 month

= 6 years + 1 year - 1 month

= 6years + 12 months - 1 month

= 6 years + 11 months

Therefore, Dalton spent 6 years and 11 months in high school.

6 0

3 years ago

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago

Write a situation that could be represented by the algebraic expression 3a + 2.15.

nordsb [41]

Answer:

5.15

Step-by-step explanation:

5.15 = 3a + 2.15

5.15 - 2.15 = 3a

3.15 = 3a

a = 0.05

I hope this helps you :)

8 0

3 years ago

Solve x^2 +11x = -10

Greeley [361]

Answer:

x = -1, -10

Step-by-step explanation:

3 0

3 years ago