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nika2105 [10]
3 years ago
12

What is the range of the given function? {(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
Range is the set of possible output values of a function. In this case, it’s (-9, -3, 0, 5, 7).
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Find the length of the arc. round your answer to nearest tenth
tigry1 [53]

41.9 mi

Step-by-step explanation:

First, we convert the angle from degree measure to radian measure:

\theta = 240°×\left(\dfrac{\pi}{180°}\right)= \dfrac{4\pi}{3}\:\text{rad}

Using the definition of an arc length s

s = r\theta

\:\:\:\:=(10\:\text{mi})\left(\dfrac{4\pi}{3}\:\text{rad}\right)

\:\:\:\:= 41.9\:\text{mi}

4 0
3 years ago
Alvin at 1/3 of a pizza for dinner and took 1/6 of it for lunch the next day . How much pizza does he have left
Inga [223]
1/3=2/6

So he ate 2/6ths of the pizza and now there is 4/6ths left.

He took 1/6ths with him for lunch so 4/6-1/6=3/6
You can simplify 3/6 to 1/2

He was 1/2 of the pizza left. 
7 0
3 years ago
Read 2 more answers
19, 36, 23, 42, 21, 33, 23, 24, 36, 42, 23, 37, 37, 33, 17
LekaFEV [45]

What is this suppose to mean

3 0
3 years ago
Pleaseeee help meeeeeee
Maslowich
That my dear your answer would be 16 degrees hope this helped
5 0
4 years ago
If sin theta= 12/13 and θ is in quadrant II, cos 2 theta= and cos theta = .
Lady bird [3.3K]

Answer:

cos2θ = -0.7041

Cos θ = -0.3847

Step-by-step explanation:

Firstly, we should understand that since θ is in quadrant 2, the value of our cosine will be negative. Only the sine is positive in quadrant 2.

Now the sine of an angle refers to the ratio of the opposite to the adjacent. And since there are three sides to a triangle, we need to find the third side which is the adjacent so that we will be able to evaluate the cosine of the angle.

What to use here is the Pythagoras’ theorem which states that the square of the hypotenuse is equal to the sum of the squares of the adjacent and the opposite.

Since Sine = opposite/hypotenuse, this means that the opposite is 12 and the hypnotist 13

Thus the adjacent let’s say d can be calculated as follows

13^2 = 12^2 + d^2

169 = 144 + d^2

d^2 = 169-144

d^2 = 25

d = √25 = ±5

Since we are on the second quadrant, the value of our adjacent is -5 since the x-coordinate on the second quadrant is negative.(negative x - axis)

The value of cos θ = Adjacent/hypotenuse = -5/13

Cos θ = -5/13

Cos θ = -0.3846

Using trigonometric formulas;

Cos 2θ = cos (θ + θ) = cos θ cos θ - sin θ sin

θ = cos^2 θ - sin^2 θ

Cos 2θ = (-5/13)^2 - (12/13)^2

Cos 2θ = 25/169 - 144/169

Cos 2θ = (25-144)/169 = -119/169

Cos 2θ = -0.7041

3 0
3 years ago
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