Can u pls explain this if u found the answer because i was not at school when they learned that lesson

Nick bought a new car.

ira [324]

Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

$A(t) = A(0)(1 - r)^t$

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:

$A(t) = A(0)(0.88)^t$ .

It halves in value at t years, for which A(t) = 0.5A(0), hence:

$A(t) = A(0)(0.88)^t$

$0.5A(0) = A(0)(0.88)^t$

$(0.88)^t = 0.5$

$\log{(0.88)^t} = \log{0.5}$

$t\log{0.88} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.88}}$

t = 5.42.

It takes 5.42 years for the car to halve in value.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

9 0

2 years ago

Reuben made 4 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 4 necklaces

zysi [14]

Answer:

$3.90

Step-by-step explanation:

The total cost was $24.40.

We know the cost for beads for each necklace is also $2.20, multiply this by four to find the cost of the beads for all the necklaces.

$2.20 × 4 = $8.80

Now we will subtract this from the total price.

$24.40 - $8.80 = $15.60

$15.60 Is the remaining cost for the pendants of all four necklaces. We will now divide this by four to find the price of a single pendant.

$15.60 ÷ 4 = $3.90

<u>This means the cost of each pendant is $3.90</u>

5 0

3 years ago

Read 2 more answers

How are angles 1,2,3,4 related in the trapezoid

Alex

Answer:

The degree measure of the four add up to 360 degrees. This is actually true of any quadrilateral. Let lower case letter a,b,c and d represent the angle of trapezoid ABCD. Then a+b+c+d= 360 degreees.

5 0

3 years ago

A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit

sergiy2304 [10]

Answer:

95% Confidence interval: (39.43, 61.58)

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ = $50.50

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation = 20

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.1447$

$=50.50 \pm 2.1447(\dfrac{20}{\sqrt{15}} ) \\\\= 50.50 \pm 11.0751 \\= (39.4249,61.5751)\\\approx (39.43, 61.58)$

95% Confidence interval: (39.43, 61.58)

8 0

3 years ago

Can someone please clearly and correctly work out Q19? Would appreciate it a lot! :)

DiKsa [7]

$x^{2} +10x+30$
I always start by moving the last term to the other side
$x^{2} +10x=-30$
To complete the square you take term 'b' , divide it by 2 then square it
$( \frac{10}{2} )^2$ = 25
We have to add 25 to what we have and what you do to one side you have to do to the other
$x^{2} +10x+25=-30+25$
$x^{2} +10x+25=-5$
Now we factor what is on the left side of the equation
$(x+5)^2=-5$
The last step is to move our right side of the equation back over
$(x+5)^2+5$ - which is your answer :)))

6 0

4 years ago