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Elenna [48]
3 years ago
11

BLANK + 308 + -126 = 450

Mathematics
2 answers:
fenix001 [56]3 years ago
5 0

Answer:

268

Step-by-step explanation:

trasher [3.6K]3 years ago
4 0

Answer:

268

Step-by-step explanation:

 450

- 126

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Kelly took a quiz on decimals that had 15 questions. She got 4/5 of those questions correct. She took another quiz on fractions
irina [24]
The first quiz (4/5 with 15 questions)

on that quiz, Kelly got 12/15 questions correct and the other quiz, she only got 10/12. since 12 is a higher number than 10 it means the answer is the first quiz.

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3 years ago
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3 years ago
e vertices of a rectangle are R(-5,-5), S(-6,-5),T(-1,1),U(-5,1) a translation maps R to the point (2,-9)
Tema [17]

Answer:

The rule of translation : (x,y)\rightarrow (x+7,y-4)

The vertices of image is R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

Step-by-step explanation:

The vertices of a rectangle are R(-5,-5), S(-6,-5), T(-1,1), U(-5,1).

It is given that a translation maps R to the point (2,-9).

Difference between x-coordinates:

-5-2=-7

Difference between y-coordinates:

-5-(-9)=-5+9=4

The x-coordinate increased by 7 and y-coordinate decreased by 4. It means the figure shifts 7 units right and 4 units down.

The rule of translation is

(x,y)\rightarrow (x+7,y-4)

The vertices of image are

R(-5,-5)\rightarrow R'(-5+7,-5-4)=R'(2,-9)

S(-6,-5)\rightarrow S'(-6+7,-5-4)=S'(1,-9)

T(-1,1)\rightarrow T'(-1+7,1-4)=T'(6,-3)

U(-5,1)\rightarrow U'(-5+7,1-4)=U'(2,-3)

Therefore, the vertices of image are R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

7 0
3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. Wellpoint provides a v
Veronika [31]

Answer:

The 95% confidence interval for the mean savings is ($60.54, $81.46).

Step-by-step explanation:

As there is no information about the population standard deviation of savings and the sample is not large, i.e. <em>n</em> = 20 < 30, we will use a <em>t</em>-confidence interval.

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}

For the data provided compute the sample mean and standard deviation as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{ X_{i}}=\frac{1}{20}\times [92+34+40+...+53+82]=71

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 9492 }{ 20 - 1} } \approx 22.35

The critical value of <em>t</em> for <em>α</em> = 0.05 and (n - 1) = 19 degrees of freedom is:

t_{\alpha/2, (n-1)}=t_{0.025, 19}=2.093

*Use a <em>t</em>-table for the value.

Compute the 95% confidence interval for the mean savings as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}\\=71\pm 2.093\times\frac{22.35}{\sqrt{20}}\\=71\pm 10.46\\=(60.54, 81.46)

Thus, the 95% confidence interval for the mean savings is ($60.54, $81.46).

3 0
3 years ago
P²- 4p - 32 = 0 solve by filling the square
Leya [2.2K]
Did u want a picture of it or just the answer
3 0
3 years ago
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