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Verizon [17]
3 years ago
11

McKenna pays $16 per month for a gym membership. In addition, she pays $2 per Pilates class.

Mathematics
2 answers:
Nina [5.8K]3 years ago
7 0

No, it is not the correct amount to be charged.

Step-by-step explanation:

  • Step 1: Given, the monthly gym membership = $16 and charges for Pilates class = $12. So charges for 12 classes = 2 × 12 = $24
  • Step 2: Calculate total charges for one month.

Total charges = Gym membership + Pilates classes = 16 + 24 = $40

⇒ So the $52 is an incorrect amount.

True [87]3 years ago
4 0

$16 per month can be changed to 16m where m represents months.

The $2 per Pilates class can be 2p where p represents Pilates classes.

An equation of y = 16m + 2p can be set up, where y represents how much McKenna is charged total for gym membership ($52)

52 = 16m + 2p

We know that McKenna attended 12 Pilates classes, and we also know that McKenna attended 1 month, so we plug this in:

52 = 16(1) + 2(12) (simplify)

52 = 16 + 24 (add 24)

52 = 40

Since this is not equal, $52 is not the correct amount to be charged.

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3 years ago
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AfilCa [17]

Answer:

Therefore the value of x is

x=1\pm\sqrt{19}i

Step-by-step explanation:

Given:

x^{2}+20=2x which is

x^{2}-2x+20=0

To Find:

x = ? using Quadratic Formula

Solution:

For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as

x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

On Comparing with above we get

a=1\\b=-2\\c=20

Substituting a , b , c in Formula method we get

x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i

Therefore the value of x is

x=1\pm\sqrt{19}i

8 0
3 years ago
How do you solv divisions like 60/19. Please someone tell me fast
MatroZZZ [7]

Answer:

The first thing you do is:        

Step-by-step explanation:

How to calculate 60 divided by 19

Here we will show you step-by-step with detailed explanation how to calculate 60 divided by 19 using long division.

Before you continue, note that in the problem 60 divided by 19, the numbers are defined as follows:

60 = dividend

19 = divisor

Step 1:

Start by setting it up with the divisor 19 on the left side and the dividend 60 on the right side like this:

           

 1 9 ⟌ 6 0  

Step 2:

The divisor (19) goes into the first digit of the dividend (6), 0 time(s). Therefore, put 0 on top:

       0    

 1 9 ⟌ 6 0  

Step 3:

Multiply the divisor by the result in the previous step (19 x 0 = 0) and write that answer below the dividend.

       0    

 1 9 ⟌ 6 0  

       0    

Step 4:

Subtract the result in the previous step from the first digit of the dividend (6 - 0 = 6) and write the answer below.

       0    

 1 9 ⟌ 6 0  

     - 0    

       6    

Step 5:

Move down the 2nd digit of the dividend (0) like this:

       0    

 1 9 ⟌ 6 0  

     - 0    

       6 0  

Step 6:

The divisor (19) goes into the bottom number (60), 3 time(s). Therefore, put 3 on top:

       0 3  

 1 9 ⟌ 6 0  

     - 0    

       6 0  

Step 7:

Multiply the divisor by the result in the previous step (19 x 3 = 57) and write that answer at the bottom:

       0 3  

 1 9 ⟌ 6 0  

     - 0    

       6 0  

      5 7  

Step 8:

Subtract the result in the previous step from the number written above it. (60 - 57 = 3) and write the answer at the bottom.

       0 3  

 1 9 ⟌ 6 0  

     - 0    

       6 0  

     - 5 7  

         3  

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%20%28%5Cfrac%7Bx%28x-2%29%7D%7B2-2e%5E2x%7D%20%29" id="TexFormula1" ti
krek1111 [17]

Answer: 0

Step-by-step explanation:

Substituting in x=0, we get

\frac{0(0-2)}{2-2e^{2}(0)}=0

7 0
2 years ago
HELP ME PLZ<br>jplz answer ill give branily ​
Maurinko [17]
The answer should be 0 I’m not sure tho
3 0
2 years ago
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