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Goshia [24]
3 years ago
12

9p- 18=27 what is p?

Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

p = 5

Step-by-step explanation:

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Four friends paid a total of $32 for movie tickets.what is the ratio $32 for 4 people written as a unit rate
eduard
$32/4 = $8 per ticket
6 0
3 years ago
If WZYX is equal to PMLN describes two quadrilaterals, which other statement is also true? I NEED THIS ANSWER ASAP
kondor19780726 [428]

Answer:

C.WXYZ equal to PNLM

Step-by-step explanation:

Look at the given statement, WZYX is equal to PMLN.

WZYX is equal to PMLN.   W corresponds to P.

WZYX is equal to PMLN.   Z corresponds to M.

WZYX is equal to PMLN.   Y corresponds to L.

WZYX is equal to PMLN.   X corresponds to N

Now look in the choices. The letters must correspond like they do above.

W must correspond to P.

WXYZ equal to P...

X must correspond to N.

WXYZ equal to PN...

Y must correspond to L.

WXYZ equal to PNL...

Z must correspond to M.

WXYZ equal to PNLM

Answer: C.WXYZ equal to PNLM

8 0
3 years ago
Read 2 more answers
Please answer quickly :’)
Virty [35]

check below for labels,

  • Full line is referred as diameter.

  • Half of diameter or from centre touching the circle is called radius.

5 0
3 years ago
When 1,250 Superscript three-fourths is written in simplest radical form, which value remains under the radical?
Dvinal [7]

The value remains under the radical is 8 ⇒ last answer

Step-by-step explanation:

Let us revise how to write the exponent as a radical

  • a^{\frac{m}{n}} can be written as \sqrt[n]{a^{m}}
  • To simplify the radical factorize the base "a" to its prime factors

Example:

  • (54)^{\frac{2}{3}}=\sqrt[3]{(54)^{2}} ,
  • Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 = 2(3)^{3}
  • \sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}
  • 2² can not go out the radical because 2 is less than 3 not divisible by 3
  • 3^{6} can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
  • \sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}

Now let us solve your problem

∵ 1250^{\frac{3}{4}}=\sqrt[4]{1250^{3}}

- Factorize 1250 to its prime factors

∵ 1250 = 2 × 5 × 5 × 5 × 5

∴ 1250=2*5^{4}

∴ \sqrt[4]{(2*5^{4})^{3}}=\sqrt[4]{2^{3}*5^{12}}

∵ 2³ can not go out the radical because 3 < 4 and not divisible by it

- 5^{12} can go out the radical because 12 can divided by 4

∵ 12 ÷ 4 = 3

∴ 5^{12} can go out the radical as 5³

∴ \sqrt[4]{1250}=5^{3}\sqrt[4]{2^{3}}

∴ \sqrt[4]{1250}=125\sqrt[4]{8}

∴ The value remains under the radical = 8

The value remains under the radical is 8

Learn more:

You can learn more about the radicals in brainly.com/question/7153188

#LearnwithBrainly

8 0
3 years ago
Can someone help me please
FinnZ [79.3K]

Answer:

1/9, 3, 27

(A / the first option listed)

Step-by-step explanation:

Here, we are given an expression with an "x" in it, and we are to evaluate possible x values, which means we plug them in as the x in the expression

first,

x = -2

3ˣ → 3⁻²

when we raise something to a negative power, we simply find the positive version of that power, and put a 1 over it:

3²  =  3 · 3 =  9

so, 3⁻² =  \frac{1}{9}  (1/9)

next,

x = 1

3ˣ → 3¹

now, here we have something raised to the power of 1, which is always itself, so  3¹ = 3

   (think of ^to the power of  as how many times we multiply that number, so 3² = 3 · 3, 3¹ = 3)

and finally,

x = 3

3ˣ → 3³

here, we can multiply 3 by itself 3 times:

3 · 3 · 3 = 27

so, 3³ = 27

[<em>important note</em><em>: when we raise something to a power, we are </em><u><em>not</em></u><em> multiplying the base number by that number, but this is a common mistake. but the exponent is how many times we are multiplying that number, which is confusing at first}</em>

So, our answers in order are:

1/9, 3, 27 (the first option listed)

hope this helps! let me know if I should clarify anything :)

8 0
2 years ago
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