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saul85 [17]
3 years ago
11

On average, a commercial airplane burns about 3.9 × 10³ milliliters of gasoline per second. There can be as many as 5.1 × 10³ ai

rplanes in the air in the United States at any given time. About how many milliliters per minutes of gasoline are burned by commercial airplanes in the United States at any given time?
Mathematics
2 answers:
Pavel [41]3 years ago
5 0
1 plane burns 60x3.9x10^3
= 234x10^3 mls per minute
Required amount =
234x10^3 x 5.1x10^3
= 11934x10^6
= 1.1934x10^10 MLS Answer
Tresset [83]3 years ago
3 0

60 x 3.9x10-3 = 234x10e3ml/minute/plane

You have 5.1x10e3 planes in the air

(234 x 5.1) (10e6) ---you add the two exponents together for this one

1193.4 x 10e6...which turns into 1.2 x 10e9

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5 0
2 years ago
List the domain and range of the relation.<br> (5,- 9), (7,7), (0, -9), (7.1) (5,9)
nalin [4]

Answer:

Domain={ 5,7,0,}

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7 0
3 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)
dybincka [34]

Answer:

amplitude; \frac{2}{3}

Phase shift; \pi units right

Period;\frac{2\pi}{3}

Step-by-step explanation:

The given function is

y=-\frac{2}{3}\cos(3t-3\pi)

This function is of the form;

y=A\sin (Bt+C)

The period is given by:

|A|=|-\frac{2}{3}|= \frac{2}{3}

The period is given by:

T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}

The phase shift is given by;

\frac{C}{B}=\frac{-\3pi}{3}=- \pi or \pi units right.

4 0
3 years ago
Trig questions:
navik [9.2K]
Question 1
Because the period is 2π, and the amplitude is 1obtain
f(x) = sin(x)
Because the horizontal shift is π, obtain
f(x) = sin(x - π)
Because the vertical shift is -4, obtain
f(x) = sin(x - π) - 4

Answer: 1. f(x) = sin(x - π) - 4

Question 2
The radius is 36/2 = 18 in.
1 revolution (360°) is the circumference, which is
2π(18) = 36π in
When the revolution is 62°, the distance traveled is
(62/360)*(36π) = (31/5)π in

Answer: 3. (31π)/5

Question 3.
Consider f(x) = 3cos(2x-π) - 1
f(0) = 3cos(-π) - 1 = -4
f(π/2) = 3cos(0) - 1 = 2
Rate of change = (2+4)/(π/2) = 12/π

From the graph, the rate of change of g(x)  is
3/(π/2) = 6/π

Consider h(x) = sin(x) - 4
h(0) = 0 - 4 = -4
h(π/2) = 1 - 4 = -3
Rate of change = (-3+4)/(π/2) = 2/π
Therefore h(x) has the smallest rate of change

Answer: h(x)

8 0
3 years ago
1/2x+2 in linear equation
Bogdan [553]

x/2+2 = 0

x+4/2 = 0

x+4 = 0

4 0
3 years ago
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