Next, remember that the vertex lies on the axis of symmetry, and the equation to find the axis of symmetry is $x=\frac{-b}{2a}$ (a = x^2 coefficient, b = x coefficient). Solve for the axis of symmetry as such:

$x=\frac{10}{2*1}=\frac{10}{2}=5$

So now that we know that the axis of symmetry is x = 5, we also know that's the vertex's x-coordinate (since the vertex falls on the axis of symmetry). Now plug in 5 for x in the original equation to solve for f(5):

$f(5)=5^2-10(5)+16\\ f(5)=25-50+16\\ f(5)=-9$

So putting it together, the vertex of this equation is (5,-9).

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2 years ago

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disa [49]

Answer is maybe that the 12 is unneeded at the top???

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2 years ago