To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).

7 0

3 years ago

Please help me with this

madreJ [45]

Answer:

the answer is the first one hope this helps

Step-by-step explanation:

3 0

3 years ago

A triangle has a base length of 12 inches and a height of 14 inches. From that

Paladinen [302]

A= bh(1/2)
a=12(14)(1/2)
a= 168(1/2)
a= 84inches

3 0

2 years ago

What is the remainder of (2x3 − 18x + 5) ÷ (x − 3)?

Hatshy [7]

I may be incorrect so verify with someone
(2×3-18x+5) ÷(x-3)
(6-18x +5) ÷ (x-3)
11-18x ÷x-3

the last part is in the image

GOOD LUCK
PLEASE GIVE ME BRAINLIEST BECAUSE THIS WAS KINDA HARD

8 0

3 years ago