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Alex73 [517]
3 years ago
12

Your friend claims it is possible for a rational function to have two vertical asymptotes. Is your friend correct? Justify your

answer.
Mathematics
1 answer:
Fudgin [204]3 years ago
7 0

Answer: True.

Step-by-step explanation:

The simpler example of this is the simpler rational function:

f(x) = 1/x

As x goes to zero from the right, the function will go asymptotically to ∞

while if x goes to zero from the left (negative region of the real values) the function will go asymptotically to -∞

So we have two vertical asymptotes.

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ehidna [41]

Answer:

y+4x=36

Step-by-step explanation:

the answer isn't in the choice

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3 years ago
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5: 6/5

6: -3

7: 2/5

8: 4/2 or 2

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2 years ago
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A function is shown in the table below. what equation represents this function?
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y=-3x+6

Step-by-step explanation:

8 0
3 years ago
Please help?
Mazyrski [523]

Answer:

23\sqrt{3}\ un^2

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\

2. Note that

A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0
3 years ago
The linear function that is represented by which table has the same slope as the graph? (the tables are the choices)
goblinko [34]
HEY THERE.

THE CORRECT ANSWER IS TABLE 3
4 0
3 years ago
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