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ValentinkaMS [17]
3 years ago
13

Can someone help me with these two proof questions?

Mathematics
1 answer:
timurjin [86]3 years ago
6 0

The proofs of above Questions is in attachment !

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Pedro is doing math exercises from a software program he recently purchased. In the program, you have to get at least 70% of the
Nookie1986 [14]
The inequality would be
0.75q ≥ 0.70(q+1)

q is defined as the number of questions he answers after the first one.  We are told he gets 75% of those correct; 75%=75/100=0.75.  This gives us 0.75q.

Since he gains proficiency on the exercises, the total number he gets correct has to be at least 70%.  This means the inequality would have the symbol greater than or equal to, as it cannot be less and have him gain proficiency.

He has already answered 1 question and answers q more; this gives us a total of q+1.  Since he gains proficiency, the cutoff was 70%; 70%=70/100=0.70.  This gives us the expression 0.70(q+1).

Our total inequality would then be 0.75q ≥ 0.70(q+1)
3 0
3 years ago
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What is 3.9 times 0.5 plus 4 5/6 divided by 3 3/7
topjm [15]
I used a math calculator to evaluate this expression you just plug it in and it gives you the answer with all the steps. use the app FX math junior, but this is the answer ; 2419/720=3.3597
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Pls help with this question please
Marina86 [1]

Answer:

x=8

Step-by-step explanation:

<h3><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u>:</u><u>-</u></h3>

RS=28

RT=3x+4

<h3><u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u>:</u><u>-</u></h3>

<u>Solve</u><u> </u><u>for</u><u> </u><u>x</u><u>.</u>

<h3><u>According</u><u> </u><u>to</u><u> </u><u>question</u><u>:</u><u>-</u></h3>

<h3>=>RS = RT</h3>

[Tangent of same circle are equal]

=>3x+4=28

=>3x=28-4

=>3x=24

=>x=\frac{24}{3}

<h3>=>x=8</h3>

<h3><u>The</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u></h3>

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3 years ago
What is 8 2/3 - 1 3/10
just olya [345]
7 11/30

Hope this helped!
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How do you message people on brainly?​
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You have to reach a certain level
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