you're correct. its to take out the greatest common factor.
I think it is:
A = 9y = 3yx
A = 9y = 3y (3)
A = 9y = 9y
A = 9y
A/9 = y?
<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>
Given expression ,
We know that,
Therefore , this can be written as ,
![\implies \sqrt[4]{13^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B4%5D%7B13%5E3%7D%20)
<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>
Given expression ,
We know that,
Therefore, this can be written as ,

Step-by-step explanation:
11.
Area of rectangle = 408 in²
Length = 3x-2 and width = x
The area of a rectangle is given by :
A = lb
(3x-2)x = 408
x = 12 inch and x = -11.33 in
Neglecting negative value,
The width of rectangle = 12 inch
The length of rectangle = 3x-2 = 3(12)-2 = 34 inch
12.
Base of triangle = 2x+2
Height = x
The area of a triangle is given by :

x = 24 cm and x = -25 cm
Neglecting negative value, x = 24 cm
Base = 2x+2 = 2(24)+2 = 50 cm
Hence, this is the required solution.