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2 years ago

In the following month 10 percent savings on other cost are expected

Mathematics

1 answer:

charle [14.2K]2 years ago

3 0

Yes agree 10 percent is expected

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An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

2 years ago

-6(w - 4) + 8W=6(w + 2)

Nesterboy [21]

Answer:

w = 3

Step-by-step explanation:

-6(w - 4) + 8W=6(w + 2)

-6w + 24 + 8w = 6w + 12

2w + 24 = 6w + 12

12 = 4w

3 = w

7 0

3 years ago

Read 2 more answers

a particular species of bamboo can grow up to 91 centimeters in a day. how fast is this in inches per hour

solniwko [45]

I would probably just do 91 times 60 since 60 min is 1 hour

8 0

3 years ago

How much money has to be invested at 2.3% interest compounded continuously to have $41,000 after 17 years?

Llana [10]

For this, we have to calculate how much money has to be invested at 2.3% interest compounded continuously to achieve $41,000 after 17 years

Formula: A= P * ( 1+r)^t
A= $41,000
r=0.023
t= 17
<span>41,000= P * (1+0.023)^17
</span>41,000= P * (1.023)^17
41,000= P * 1.4719
P= 41,000 : 1.4719
P= $27,731.59
Therefore, the answer is C. $27,731.59
I checked by doing the opposite, and I got $41,000.01, which is the closest to the question<span>
</span>

7 0

3 years ago

Math question <3 <3 <3

sleet_krkn [62]

The correct answer is about two hours. Hope this helps.

6 0

3 years ago