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iragen [17]
3 years ago
10

Someone please help me

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

the equation has no answers

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What is the area of the parallelogram? Show your work. (5 points)
stepan [7]
Part A. The formula for finding the area of a parallelogram is A=bh where A is the area, b is the base and h is height.
A=bh where b=8 feet ,h=3/4 foot and A=?
A=8*3/4
A=6 feet The area of the parallelogram is 6 feet square
Part B.You can decompose a parallelogram into two triangles by drawing a diagonal from one end to the another.The formula for finding the area of each triangle is A= 1/2bh where A is area b is base and h is height.Therefore:
A=1/2bh where b=8 h is 3/4 and A=?
A=1/2*8*3/4
A=3 feet square. Therefore the area of each triangle is 3 feet square.


4 0
3 years ago
Can someone answer a b c or d? thanks!
Korolek [52]

Answer:

Wdym? Do you have another question on your pf or something?

Step-by-step explanation:

Let me know if I can help!

Have a nice day <3

6 0
2 years ago
Read 2 more answers
Solve for x 4(2x+9)=-44+8
Andreas93 [3]

Answer:

x=-9

Step-by-step explanation:

distribute 4 into the parentheses

8x+36=-44+8

add -44+8

and u get 8x+36=-36

subtract the 36 on both sides and leave u with

8x=-72

divide 8 on both sides

and ur answer is -9

i dont think this make sense but hope this helps

5 0
3 years ago
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( There are two similar triangles on the graph below. Use the graph to answer the questions. You must answer each question AND e
Evgen [1.6K]

Answer:

The Slope of both the lines is the same.

Step-by-step explanation:

Given two co-ordinates (x1, y1) and (x2, y2), the slope of a line can be found using the formula:

slope = \frac{y2-y1}{x2-x1}

For the diagonal line of the first triangle, the coordinates are (0, 0) and (2, 1)

slope of diagonal line of first  triangle = \frac{1 - 0}{2 - 0} = \frac{1}{2}

For the diagonal line of the large triangle, the coordinates are (2, 1) and (6, 3)

slope of diagonal line of second  triangle = \frac{3-1}{6-2} = \frac{2}{4} = \frac{1}{2}

7 0
3 years ago
Read 2 more answers
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
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