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ankoles [38]
3 years ago
14

An inexpensive and accurate method of measuring the quantity of electricity passing through a circuit is to pass it through a so

lution of a metal ion and weigh the metal deposited. A silver electrode immersed in an Ag solution weighs 1.7854 g before the current passes and weighs 1.9274 g after the current has passed. how many coulombus have passed?
Chemistry
1 answer:
vovangra [49]3 years ago
5 0

Answer:

127.013 C

Explanation:

-We apply Faraday's First Law of Electrolysis which states that the mass,m of a substance deposited is directly proportional to the current,Q passed through it:

m=ZQ

Where Z is the proportionality constant(g/C)

-The current can therefore be calculated as:

m=ZQ\\\\Z=\frac{Atomic \ mass \ of \ substance}{Faraday's \ Constant}\\\\=\frac{107.8682}{96485}\\\\=0.001118\ g/C\\\\\\Q=\frac{m}{Z}\\\\m=\bigtriangleup m=1.9274-1.7854=0.142 \ g\\\\\therefore Q=\frac{0.142\ g}{0.001118g/C}\\\\=127.013 \ C

Hence, the amount of current through the circuit is 127.013 C

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Calculate the number of Cl atoms that are in 1.1 x 10^-21 moles of Cl atoms.
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According to Avogadro's number there are 62.53 atoms of chlorine in 1.1x 10^-21 moles of Cl atoms.

<h3>What is Avogadro's number?</h3>

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number or number of moles×Avogadro's number.

ON substitution in above formula number of atoms=1.1×10²¹×6.023×10²³=62.53 atoms

Thus, there are 62.53 chlorine  atoms in 1.1x 10^-21 moles of Cl atoms.

Learn more about Avogadro's number,here:

brainly.com/question/11907018

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If C and Cl combined to make a compound, would it be covalent or ionic?
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