15.g express your answer as integer
1 answer:
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<u>Answer:</u> The pH of the resulting solution will be 3.60
<u>Explanation:</u>
Molarity is calculated by using the equation:
......(1)
We are given:
Molarity of formic acid = 0.100 M
Molarity of potassium formate = 0.100 M
Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
Molarity of KOH = 1.00 M
Volume of solution = 7 mL = 0.007 L
Putting values in equation 1, we get:
The chemical equation for the reaction of formic acid and KOH follows:
I: 0.042 0.007 0.042
C: -0.007 -0.007 +0.007
E: 0.035 - 0.049
Volume of solution = [420 + 7] = 427 mL = 0.427 L
To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:
.......(2)
Given values:
Putting values in equation 2, we get:
Hence, the pH of the resulting solution will be 3.60